我一直在寻找排序这样的JSON对象的时间
{"results": [ { "layerId": 5, "layerName": "Pharmaceutical Entities", "attributes": { "OBJECTID": "35", "FACILITYTYPE": "Pharmacy", "FACILITYSUBTYPE": "24 Hr Pharmacy", "COMMERCIALNAME_E": "SADD MAARAB PHARMACY", }, "geometryType": "esriGeometryPoint", }, { "layerId": 5, "layerName": "Pharmaceutical Entities", "attributes": { "OBJECTID": "1", "FACILITYTYPE": "Pharmacy", "FACILITYSUBTYPE": "24 Hr Pharmacy", "COMMERCIALNAME_E": "GAYATHY HOSPITAL PHARMACY", }, "geometryType": "esriGeometryPoint", }, { "layerId": 5, "layerName": "Pharmaceutical Entities", "attributes": { "OBJECTID": "255", "FACILITYTYPE": "Pharmacy", "FACILITYSUBTYPE": "24 Hr Pharmacy", "COMMERCIALNAME_E": "AL DEWAN PHARMACY", }, "geometryType": "esriGeometryPoint", } ]}
按字母顺序按“ COMMERCIALNAME_E”的值获取
{"results": [ { "layerId": 5, "layerName": "Pharmaceutical Entities", "attributes": { "OBJECTID": "255", "FACILITYTYPE": "Pharmacy", "FACILITYSUBTYPE": "24 Hr Pharmacy", "COMMERCIALNAME_E": "AL DEWAN PHARMACY", }, "geometryType": "esriGeometryPoint", }, { "layerId": 5, "layerName": "Pharmaceutical Entities", "attributes": { "OBJECTID": "1", "FACILITYTYPE": "Pharmacy", "FACILITYSUBTYPE": "24 Hr Pharmacy", "COMMERCIALNAME_E": "GAYATHY HOSPITAL PHARMACY", }, "geometryType": "esriGeometryPoint", }, { "layerId": 5, "layerName": "Pharmaceutical Entities", "attributes": { "OBJECTID": "35", "FACILITYTYPE": "Pharmacy", "FACILITYSUBTYPE": "24 Hr Pharmacy", "COMMERCIALNAME_E": "SADD MAARAB PHARMACY", }, "geometryType": "esriGeometryPoint", } ]}
我找不到任何可以做到这一点的代码。谁能给我些帮助吗？
function sortJsonArrayByProperty(objArray, prop, direction){ if (arguments.length<2) throw new Error("sortJsonArrayByProp requires 2 arguments"); var direct = arguments.length>2 ? arguments[2] : 1; //Default to ascending if (objArray && objArray.constructor===Array){ var propPath = (prop.constructor===Array) ? prop : prop.split("."); objArray.sort(function(a,b){ for (var p in propPath){ if (a[propPath[p]] && b[propPath[p]]){ a = a[propPath[p]]; b = b[propPath[p]]; } } // convert numeric strings to integers a = a.match(/^\d+$/) ? +a : a; b = b.match(/^\d+$/) ? +b : b; return ( (a < b) ? -1*direct : ((a > b) ? 1*direct : 0) ); }); } } sortJsonArrayByProperty(results, 'attributes.OBJECTID'); sortJsonArrayByProperty(results, 'attributes.OBJECTID', -1);
更新：请勿更改
function sortByProperty(objArray, prop, direction){ if (arguments.length<2) throw new Error("ARRAY, AND OBJECT PROPERTY MINIMUM ARGUMENTS, OPTIONAL DIRECTION"); if (!Array.isArray(objArray)) throw new Error("FIRST ARGUMENT NOT AN ARRAY"); const clone = objArray.slice(0); const direct = arguments.length>2 ? arguments[2] : 1; //Default to ascending const propPath = (prop.constructor===Array) ? prop : prop.split("."); clone.sort(function(a,b){ for (let p in propPath){ if (a[propPath[p]] && b[propPath[p]]){ a = a[propPath[p]]; b = b[propPath[p]]; } } // convert numeric strings to integers a = a.match(/^\d+$/) ? +a : a; b = b.match(/^\d+$/) ? +b : b; return ( (a < b) ? -1*direct : ((a > b) ? 1*direct : 0) ); }); return clone; } const resultsByObjectId = sortByProperty(results, 'attributes.OBJECTID'); const resultsByObjectIdDescending = sortByProperty(results, 'attributes.OBJECTID', -1);
