绝对有可能并且鼓励创建自定义容器视图。这就是Android所谓的复合控件。所以：

public class MyCustomView extends RelativeLayout {
    private LinearLayout mContentView;

    public MyCustomView(Context context) {
        this(context, null);
    }

    public MyCustomView(Context context, AttributeSet attrs) {
        this(context, attrs, 0);
    }

    public MyCustomView(Context context, AttributeSet attrs, int defStyle) {
        super(context, attrs, defStyle);
        //Inflate and attach your child XML
        LayoutInflater.from(context).inflate(R.layout.custom_layout, this);
        //Get a reference to the layout where you want children to be placed
        mContentView = (LinearLayout) findViewById(R.id.content);

        //Do any more custom init you would like to access children and do setup
    }

    @Override
    public void addView(View child, int index, ViewGroup.LayoutParams params) {
        if(mContentView == null){
            super.addView(child, index, params);
        } else {
            //Forward these calls to the content view
            mContentView.addView(child, index, params);
        }
    }
}

您可以根据需要覆盖尽可能多的版本addView()，但最后它们都会回调到我在样本中放置的版本。仅重写此方法将使框架将在XML标记内找到的所有子代传递给特定的子代容器。

然后像这样修改XML：

RES /布局/custom_layout.xml

<merge>
  <SomeView />
  <SomeOtherView />
  <!-- maybe more layout stuff here later -->
  <LinearLayout
      android:id="@+id/content" />
</merge>

使用的原因<merge>是简化层次结构。所有子视图都将附加到您的自定义类（即）上RelativeLayout。如果不使用<merge>，则最终会在所有子项上RelativeLayout附加一个RelativeLayout附加项，这可能会引起问题。

高温超导