一尘不染

如何使用JPA Criteria查询编写此查询?

java

谁能帮助我获取下面提到的JPA查询的JPA标准查询。

SELECT p,l FROM Person p 
LEFT JOIN Language l ON (p.language = l.language and l.locale like :locale) 
AND p.name like :name 
AND p.time BETWEEN :startDate 
AND :endDate order by name asc

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2020-12-03

共1个答案

一尘不染

假设Person与语言有关,这就是您在较早的Hibernate中所做的事情:

Criteria criteria = entityManager.createCriteria(Person.class);
Criteria languageCriteria = criteria.createCriteria("language");

languageCriteria.add(Restrictions.like("locale", locale));

criteria.add(Restrictions.like("name", name));
criteria.add(Restrictions.between("time", startDate, endDate));

criteria.addOrder(Order.asc("name"));

我第一次尝试使用JPA 2.0:

CriteriaBuilder builder = entityManager.getCriteriaBuilder();
CriteriaQuery<Person> criteria = builder.createCriteria(Person.class);
Root<Person> pRoot = criteria.from(Person.class);
Join<Person, Language> langJoin = criteria.join("language", JoinType.LEFT);

Predicate conjunction = builder.conjunction();

criteria.where(builder.and(
    builder.like(langJoin.get(Language_.locale), locale),
    builder.like(pRoot.get(Person_.name), name),
    builder.between(pRoot.get(Person_.time), startDate, endDate));

criteria.orderBy(builder.asc(pRoot.get(Person_.name)));

请让我知道这是否适合您。

编辑: 更新查询以仅使用一个where呼叫。

2020-12-03