我目前有一些单元测试,它们共享一组通用的测试。这是一个例子:
import unittest class BaseTest(unittest.TestCase): def testCommon(self): print 'Calling BaseTest:testCommon' value = 5 self.assertEquals(value, 5) class SubTest1(BaseTest): def testSub1(self): print 'Calling SubTest1:testSub1' sub = 3 self.assertEquals(sub, 3) class SubTest2(BaseTest): def testSub2(self): print 'Calling SubTest2:testSub2' sub = 4 self.assertEquals(sub, 4) if __name__ == '__main__': unittest.main()
上面的输出是:
Calling BaseTest:testCommon .Calling BaseTest:testCommon .Calling SubTest1:testSub1 .Calling BaseTest:testCommon .Calling SubTest2:testSub2 . ---------------------------------------------------------------------- Ran 5 tests in 0.000s OK
有没有办法重写上面的内容,这样testCommon就不会调用第一个?
testCommon
编辑: 而不是运行上面的5个测试,我希望它仅运行4个测试,其中2个来自SubTest1,另外2个来自SubTest2。似乎Python unittest自己在运行原始的BaseTest,我需要一种机制来防止这种情况的发生。
使用多重继承,因此具有通用测试的类本身不会从TestCase继承。
import unittest class CommonTests(object): def testCommon(self): print 'Calling BaseTest:testCommon' value = 5 self.assertEquals(value, 5) class SubTest1(unittest.TestCase, CommonTests): def testSub1(self): print 'Calling SubTest1:testSub1' sub = 3 self.assertEquals(sub, 3) class SubTest2(unittest.TestCase, CommonTests): def testSub2(self): print 'Calling SubTest2:testSub2' sub = 4 self.assertEquals(sub, 4) if __name__ == '__main__': unittest.main()