一尘不染

如何在Pyspark中的时间序列数据上使用滑动窗口转换数据

python

我正在尝试根据时间序列数据上的滑动窗口提取特征。在Scala中,似乎有一个sliding基于此帖子和文档的功能

import org.apache.spark.mllib.rdd.RDDFunctions._

sc.parallelize(1 to 100, 10)
  .sliding(3)
  .map(curSlice => (curSlice.sum / curSlice.size))
  .collect()

我的问题是PySpark是否有类似的功能?或者,如果还没有这样的功能,我们如何实现类似的滑动窗口转换?


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2020-12-20

共1个答案

一尘不染

据我所知,sliding函数在Python中不可用,SlidingRDD是私有类,不能在外部访问MLlib

如果要sliding在现有的RDD上使用,则可以这样创建可怜人sliding

def sliding(rdd, n):
    assert n > 0
    def gen_window(xi, n):
        x, i = xi
        return [(i - offset, (i, x)) for offset in xrange(n)]

    return (
        rdd.
        zipWithIndex(). # Add index
        flatMap(lambda xi: gen_window(xi, n)). # Generate pairs with offset
        groupByKey(). # Group to create windows
        # Sort values to ensure order inside window and drop indices
        mapValues(lambda vals: [x for (i, x) in sorted(vals)]).
        sortByKey(). # Sort to makes sure we keep original order
        values(). # Get values
        filter(lambda x: len(x) == n)) # Drop beginning and end

或者,您可以尝试这样的操作(在的帮助下toolz

from toolz.itertoolz import sliding_window, concat

def sliding2(rdd, n):
    assert n > 1

    def get_last_el(i, iter):
        """Return last n - 1 elements from the partition"""
        return  [(i, [x for x in iter][(-n + 1):])]

    def slide(i, iter):
        """Prepend previous items and return sliding window"""
        return sliding_window(n, concat([last_items.value[i - 1], iter]))

    def clean_last_items(last_items):
        """Adjust for empty or to small partitions"""
        clean = {-1: [None] * (n - 1)}
        for i in range(rdd.getNumPartitions()):
            clean[i] = (clean[i - 1] + list(last_items[i]))[(-n + 1):]
        return {k: tuple(v) for k, v in clean.items()}

    last_items = sc.broadcast(clean_last_items(
        rdd.mapPartitionsWithIndex(get_last_el).collectAsMap()))

    return rdd.mapPartitionsWithIndex(slide)
2020-12-20