我需要找出客户的等级。在这里,我为我的需求添加了相应的ANSI标准SQL查询。请帮助我将其转换为MySQL。
SELECT RANK() OVER (PARTITION BY Gender ORDER BY Age) AS [Partition by Gender], FirstName, Age, Gender FROM Person
有什么功能可以找出MySQL的排名吗?
一种选择是使用排名变量,例如:
SELECT first_name, age, gender, @curRank := @curRank + 1 AS rank FROM person p, (SELECT @curRank := 0) r ORDER BY age;
该(SELECT @curRank := 0)部分允许变量初始化,而无需单独的SET命令。
(SELECT @curRank := 0)
SET
测试用例:
CREATE TABLE person (id int, first_name varchar(20), age int, gender char(1)); INSERT INTO person VALUES (1, 'Bob', 25, 'M'); INSERT INTO person VALUES (2, 'Jane', 20, 'F'); INSERT INTO person VALUES (3, 'Jack', 30, 'M'); INSERT INTO person VALUES (4, 'Bill', 32, 'M'); INSERT INTO person VALUES (5, 'Nick', 22, 'M'); INSERT INTO person VALUES (6, 'Kathy', 18, 'F'); INSERT INTO person VALUES (7, 'Steve', 36, 'M'); INSERT INTO person VALUES (8, 'Anne', 25, 'F');
结果:
+------------+------+--------+------+ | first_name | age | gender | rank | +------------+------+--------+------+ | Kathy | 18 | F | 1 | | Jane | 20 | F | 2 | | Nick | 22 | M | 3 | | Bob | 25 | M | 4 | | Anne | 25 | F | 5 | | Jack | 30 | M | 6 | | Bill | 32 | M | 7 | | Steve | 36 | M | 8 | +------------+------+--------+------+ 8 rows in set (0.02 sec)