如果在命令提示符终端中启动python并尝试打开一些url，尽管名称可以通过DNS解析，但我得到以下结果：

C:\Windows\system32>nslookup www.google.de
Nicht-autorisierende Antwort:
Name:    www-cctld.l.google.com
Address:  173.194.69.94
Aliases:  www.google.de
C:\Windows\system32>C:\Python27\python.exe
Python 2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import urllib
>>> urllib.urlopen("http://www.google.de")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python27\lib\urllib.py", line 84, in urlopen
    return opener.open(url)
  File "C:\Python27\lib\urllib.py", line 205, in open
    return getattr(self, name)(url)
  File "C:\Python27\lib\urllib.py", line 342, in open_http
    h.endheaders(data)
  File "C:\Python27\lib\httplib.py", line 951, in endheaders
    self._send_output(message_body)
  File "C:\Python27\lib\httplib.py", line 811, in _send_output
    self.send(msg)
  File "C:\Python27\lib\httplib.py", line 773, in send
    self.connect()
  File "C:\Python27\lib\httplib.py", line 754, in connect
    self.timeout, self.source_address)
  File "C:\Python27\lib\socket.py", line 553, in create_connection
    for res in getaddrinfo(host, port, 0, SOCK_STREAM):
IOError: [Errno socket error] [Errno 11001] getaddrinfo failed
>>>

我禁用了防火墙，以管理员身份启动命令提示符，但这几乎是我能想到的。nslookup可以正常工作，所以我看不出有什么问题。有什么建议？