我已经完成了一次Google搜索,并搜索了我的两本python初学者书籍,以查找执行此操作的方法。我认为这必须是一个简单的任务。基本上,我正在与python一起使用pygame。
我希望如果我单击button1_image,它会更改为button1select_image,对吗?如果单击button2_image,它将button1select_image设置回button1_image,而button2_image更改为button2select_image。
所以我想知道的是这是一个简单的if else语句还是更复杂的语句。显然,这些按钮稍后会执行其他操作,但是我无法找到基于如何通过单击用户鼠标来执行类似操作的教程。
# Button Mouse Click Image Change # Demonstrates changing from one button image to another based on click of mouse. from livewires import games, color games.init(screen_width = 281, screen_height = 500, fps = 50) button1_image = games.load_image("button1.png", transparent = False) button1 = games.Sprite(image = button1_image, x = 28,y = 18) games.screen.add(button1) button1select_image = games.load_image("button1select.png", transparent = False) button1select = games.Sprite(image = button1select_image, x = 28,y = 18) games.screen.add(button1select) button2_image = games.load_image("button2.png", transparent = False) button2 = games.Sprite(image = button2_image, x = 56,y = 18) games.screen.add(button2) button2select_image = games.load_image("button2select.png", transparent = False) button2select = games.Sprite(image = button2select_image, x = 56,y = 18) games.screen.add(button2select) games.screen.mainloop()
在这里,我进行了简单介绍,以展示鼠标的工作原理。该行if event.button == 1:检查是否已按下鼠标左键,如果要使用鼠标右键,请将1更改为2。
if event.button == 1:
import pygame, sys from pygame.locals import * TIMER = 30 SCREEN_X = 200 SCREEN_Y = 200 screen = pygame.display.set_mode((SCREEN_X, SCREEN_Y)) clock = pygame.time.Clock() #tick-tock ending = button1 = button2 = False corner1 = (28,18) #Top Left corner of button 1 corner2 = (56,18) #Top Left corner of button 2 image_length = 100 #length of the buttons image_height = 100 #height of the buttons counter = 0 #Main Loop: while ending==False: counter+=1 clock.tick(TIMER) for event in pygame.event.get(): if event.type == KEYDOWN: if event.key == K_ESCAPE: ending=True # Time to leave print("Game Stopped Early by user") elif event.type == MOUSEBUTTONDOWN: if event.button == 1: mouse_x, mouse_y = event.pos if (mouse_x >= corner1[0]) and (mouse_x <= corner1[0]+image_length) and (mouse_y >= corner1[1]) and (mouse_y <= corner1[1]+image_height): print ("Button one is selected") button1=True button2=False elif (mouse_x >= corner2[0]) and (mouse_x <= corner2[0]+image_length) and (mouse_y >= corner2[1]) and (mouse_y <= corner2[1]+image_height): print ("Button two is selected") button1=False button2=True else: print ("That's not a button") button1=False button2=False if counter == TIMER: #prints the statements once a second counter=0 if button1==True: print ("Button one is currently selected") elif button2==True: print ("Button two is currently selected") else: print ("No buttons currently selected")
在底部的打印语句中。如果button1或button2变量分别为,则只需将选择的图像用于按钮1或2 True。否则将是如果未选择任何图像,则将两个图像都作为未选择的按钮。如果您不知道如何使用图像等,请在此处查看:http : //www.pygame.org/docs/确实对我有所帮助。自己尝试一下,如果仍然遇到问题,Stack Exchange仍然会在这里提出您的问题:)
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