根据pygame中的点击更改图片

一尘不染

根据pygame中的点击更改图片

python

我已经完成了一次Google搜索，并搜索了我的两本python初学者书籍，以查找执行此操作的方法。我认为这必须是一个简单的任务。基本上，我正在与python一起使用pygame。

我希望如果我单击button1_image，它会更改为button1select_image，对吗？如果单击button2_image，它将button1select_image设置回button1_image，而button2_image更改为button2select_image。

所以我想知道的是这是一个简单的if
else语句还是更复杂的语句。显然，这些按钮稍后会执行其他操作，但是我无法找到基于如何通过单击用户鼠标来执行类似操作的教程。

# Button Mouse Click Image Change
# Demonstrates changing from one button image to another based on click of mouse.

from livewires import games, color

games.init(screen_width = 281, screen_height = 500, fps = 50)

button1_image = games.load_image("button1.png", transparent = False)
button1 = games.Sprite(image = button1_image, x = 28,y = 18)
games.screen.add(button1)

button1select_image = games.load_image("button1select.png", transparent = False)
button1select = games.Sprite(image = button1select_image, x = 28,y = 18)
games.screen.add(button1select)

button2_image = games.load_image("button2.png", transparent = False)
button2 = games.Sprite(image = button2_image, x = 56,y = 18)
games.screen.add(button2)

button2select_image = games.load_image("button2select.png", transparent = False)
button2select = games.Sprite(image = button2select_image, x = 56,y = 18)
games.screen.add(button2select)

games.screen.mainloop()

阅读 519

2021-01-20

共1个答案

一尘不染

在这里，我进行了简单介绍，以展示鼠标的工作原理。该行if event.button == 1:检查是否已按下鼠标左键，如果要使用鼠标右键，请将1更改为2。

import pygame, sys
from pygame.locals import *

TIMER = 30
SCREEN_X = 200
SCREEN_Y = 200

screen = pygame.display.set_mode((SCREEN_X, SCREEN_Y))
clock = pygame.time.Clock() #tick-tock

ending = button1 = button2 = False

corner1 = (28,18)  #Top Left corner of button 1
corner2 = (56,18)  #Top Left corner of button 2

image_length = 100 #length of the buttons
image_height = 100 #height of the buttons

counter = 0

#Main Loop:
while ending==False:
    counter+=1
    clock.tick(TIMER)
    for event in pygame.event.get():
        if event.type == KEYDOWN:
            if event.key == K_ESCAPE:
                ending=True # Time to leave
                print("Game Stopped Early by user")
        elif event.type == MOUSEBUTTONDOWN:
            if event.button == 1:
                mouse_x, mouse_y = event.pos
                if (mouse_x >= corner1[0]) and (mouse_x <= corner1[0]+image_length) and (mouse_y >= corner1[1]) and (mouse_y <= corner1[1]+image_height):
                    print ("Button one is selected")
                    button1=True
                    button2=False
                elif (mouse_x >= corner2[0]) and (mouse_x <= corner2[0]+image_length) and (mouse_y >= corner2[1]) and (mouse_y <= corner2[1]+image_height):
                    print ("Button two is selected")
                    button1=False
                    button2=True
                else:
                    print ("That's not a button")
                    button1=False
                    button2=False
    if counter == TIMER:  #prints the statements once a second
        counter=0
        if button1==True:
            print ("Button one is currently selected")
        elif button2==True:
            print ("Button two is currently selected")
        else:
            print ("No buttons currently selected")

在底部的打印语句中。如果button1或button2变量分别为，则只需将选择的图像用于按钮1或2
True。否则将是如果未选择任何图像，则将两个图像都作为未选择的按钮。如果您不知道如何使用图像等，请在此处查看：http
:
//www.pygame.org/docs/确实对我有所帮助。自己尝试一下，如果仍然遇到问题，Stack
Exchange仍然会在这里提出您的问题:)

希望能帮助到你

2021-01-20