我正在使用BeautifulSoup解析HTML表，如下所示：

for tr in table_body.find_all('tr'):      
            for td in tr:  
                if td.text == 'Description':
                    description = td.find_next('td').text
                if td.text == 'Category':
                    category = td.find_next('td').text                             
                if td.text == 'Department':
                    department = td.find_next('td').text                             
                if td.text == 'Justification':
                    justification = td.find_next('td').text
print(description, category, department, justification)

我将多个if语句重构为一个函数：

def html_check(td, text):
        if td.text == text:
            value = td.find_next('td').text
            return value

像这样被称为：

for tr in table_body.find_all('tr'):      
            for td in tr:  
                description= html_check(td, 'Description')
                category = html_check(td, 'Category')
                department = html_check(td, 'Department')
                justification = html_check(td, 'Justification')
print(description, category, department, justification)

我的问题是，当函数html_check找不到匹配项时，它将返回None，将被打印出来。这是不希望的。

有什么方法可以使此函数仅在满足if条件时才返回值？