我正在尝试扩展Python,datetime.timedelta以用于越野比赛的结果。我想从格式为string的对象构造一个对象u"mm:ss.s"。我可以使用工厂设计模式和@classmethod注释来完成此操作。我将如何通过覆盖__init__和/或完成相同的任务__new__?
datetime.timedelta
u"mm:ss.s"
@classmethod
__init__
__new__
使用下面的代码,构造一个对象会引发TypeError。请注意,__init__未调用,因为'in my __init__'未打印。
'in my __init__'
import datetime import re class RaceTimedelta(datetime.timedelta): def __init__(self, timestr = ''): print 'in my __init__' m = re.match(r'(\d+):(\d+\.\d+)', timestr) if m: mins = int(m.group(1)) secs = float(m.group(2)) super(RaceTimedelta, self).__init__(minutes = mins, seconds = secs) else: raise ValueError('timestr not in format u"mm:ss.d"')
这是错误:
>>> from mytimedelta import RaceTimedelta >>> RaceTimedelta(u'24:45.7') Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: unsupported type for timedelta days component: unicode >>>
如果将代码从__init__移至__new__,则会得到以下结果。注意这次,输出显示我的__new__函数被调用了。
>>> RaceTimedelta(u'24:45.7') in my __new__ Traceback (most recent call last): File "<stdin>", line 1, in <module> File "mytimedelta.py", line 16, in __new__ super(RaceTimedelta, self).__new__(minutes = mins, seconds = secs) TypeError: datetime.timedelta.__new__(): not enough arguments >>>
显然,timedelta对象是不可变的,这意味着它们的值实际上是在类的__new__()方法中设置的- 因此您需要覆盖该方法而不是其方法__init__():
timedelta
__new__()
__init__()
import datetime import re class RaceTimedelta(datetime.timedelta): def __new__(cls, timestr=''): m = re.match(r'(\d+):(\d+\.\d+)', timestr) if m: mins, secs = int(m.group(1)), float(m.group(2)) return super(RaceTimedelta, cls).__new__(cls, minutes=mins, seconds=secs) else: raise ValueError('timestr argument not in format "mm:ss.d"') print RaceTimedelta(u'24:45.7')
输出:
0:24:45.700000
顺便说一句,您为timestr关键字参数提供默认值会被视为非法并引发,我觉得很奇怪ValueError。
timestr
ValueError