一个简单的程序，用于计算数字平方并存储结果：

    import time
    from joblib import Parallel, delayed
    import multiprocessing

    array1 = [ 0 for i in range(100000) ]

    def myfun(i):
        return i**2

    #### Simple loop ####
    start_time = time.time()

    for i in range(100000):
        array1[i]=i**2

    print( "Time for simple loop         --- %s seconds ---" % (  time.time()
                                                               - start_time
                                                                 )
            )
    #### Parallelized loop ####
    start_time = time.time()
    results = Parallel( n_jobs  = -1,
                        verbose =  0,
                        backend = "threading"
                        )(
                        map( delayed( myfun ),
                             range( 100000 )
                             )
                        )
    print( "Time for parallelized method --- %s seconds ---" % (  time.time()
                                                               - start_time
                                                                 )
            )

    #### Output ####
    # >>> ( executing file "Test_vr20.py" )
    # Time for simple loop         --- 0.015599966049194336 seconds ---
    # Time for parallelized method --- 7.763299942016602 seconds ---

这两个选项的数组处理是否可能有所不同？我的实际程序会有一些更复杂的东西，但这 是我需要尽可能简单地并行化的一种计算方式 ，但没有这种结果。

System Model: HP ProBook 640 G2, Windows 7,
              IDLE for Python System Type: x64-based PC Processor:
              Intel(R) Core(TM) i5-6300U CPU @ 2.40GHz,
              2401 MHz,
              2 Core(s),
              4 Logical Processor(s)