样品表
CustomerId | VoucherId | CategoryId | StartDate | EndDate ------------------------------------------------------------- 10 | 1 | 1 | 2013-09-01| 2013-09-30 10 | 1 | 2 | 2013-09-01| 2013-09-30 11 | 2 | 1 | 2013-09-01| 2013-11-30 11 | 2 | 2 | 2013-09-01| 2013-11-30 11 | 2 | 3 | 2013-09-01| 2013-11-30 10 | 3 | 1 | 2013-10-01| 2013-12-31 10 | 3 | 2 | 2013-10-01| 2013-12-31 11 | 4 | 1 | 2013-12-01| 2014-04-30
在上面的示例记录中,我想找出客户凭证涵盖的总月数
我需要形式的输出
CustomerId | Months -------------------- 10 | 4 11 | 8
问题在于,凭证可以有多行用于不同的CategoryIds …
我计算出凭证涵盖的月份为DATEDIFF(MM,StartDate,EndDate)+1 …
当我应用SUM(DATEDIFF(MM,StartDate,EndDate))GROUP BY VoucherId,StartDate,EndDate时,由于VoucherId的多行,我给出了错误的结果。
我得到这样的东西…
CustomerId | Months -------------------- 10 | 8 11 | 14
在这种情况下CategoryId是无用的
谢谢
[sql fiddle demo](http://www.sqlfiddle.com/#!3/811a6/3/0)
此SQL Fiddle解决了您的疑虑。您需要生成一个Calendar表,以便您可以将日期添加到其中。然后,您可以为每个客户计算不同的MonthYears。
create table test( CustomerId int, StartDate date, EndDate date ) insert into test values (10, '9/1/2013', '9/30/2013'), (10, '9/1/2013', '9/30/2013'), (11, '9/1/2013', '11/30/2013'), (11, '9/1/2013', '11/30/2013'), (11, '9/1/2013', '11/30/2013'), (10, '10/1/2013', '12/31/2013'), (10, '10/1/2013', '12/31/2013'), (11, '12/1/2013', '4/30/2014') create table calendar( MY varchar(10), StartDate date, EndDate date ) insert into calendar values ('9/2013', '9/1/2013', '9/30/2013'), ('10/2013', '10/1/2013', '10/31/2013'), ('11/2013', '11/1/2013', '11/30/2013'), ('12/2013', '12/1/2013', '12/31/2013'), ('1/2014', '1/1/2014', '1/31/2014'), ('2/2014', '2/1/2014', '2/28/2014'), ('3/2014', '3/1/2014', '3/31/2014'), ('4/2014', '4/1/2014', '4/30/2014') select t.CustomerId, count(distinct c.MY) from test t inner join calendar c on t.StartDate <= c.EndDate and t.EndDate >= c.StartDate group by t.CustomerId