我有一个用于“个人档案”的表,以行样式存储个人档案属性值,例如:
[ProfileID] [PropertyDefinitionID] [PropertyValue] 1 6 Jone 1 7 Smith 1 8 Mr 1 3 50000
和另一个用于属性定义的表:
[PropertyDefinitionID] [PropertyName] 6 FirstName 7 LastName 8 Prefix 3 Salary
如何使用PIVOT或以任何其他方式以这种方式显示它:
PIVOT
[ProfileID] [FirstName] [LastName] [Salary] 1 Jone Smith 5000
不用PIVOT关键字就可以轻松完成此操作,只需将其分组即可
select P.ProfileID, min(case when PD.PropertyName = 'FirstName' then P.PropertyValue else null end) as FirstName, min(case when PD.PropertyName = 'LastName' then P.PropertyValue else null end) as LastName, min(case when PD.PropertyName = 'Salary' then P.PropertyValue else null end) as Salary from Profiles as P left outer join PropertyDefinitions as PD on PD.PropertyDefinitionID = P.PropertyDefinitionID group by P.ProfileID
您也可以使用PIVOT关键字执行此操作
select * from ( select P.ProfileID, P.PropertyValue, PD.PropertyName from Profiles as P left outer join PropertyDefinitions as PD on PD.PropertyDefinitionID = P.PropertyDefinitionID ) as P pivot ( min(P.PropertyValue) for P.PropertyName in ([FirstName], [LastName], [Salary]) ) as PIV