MS Access中的列到行

一尘不染

MS Access中的列到行

sql

我试图在MS Access中创建一个查询，以最终从中获取输出：

Name        Cat 1   Cat 2   Cat 3   Cat 4   Cat 5   Cat 6
Joe         2       12      10      1       0       0
Bob         0       0       0       0       0       0
Jody        2       4       3       1       2       0
Harry       0       4       14      0       2       0

对于这样的事情：

Name        Joe     Bob     Jody    Harry
Cat 1       2       0       2       0
Cat 2       12      0       4       4
Cat 3       10      0       3       14

这有可能吗？

编辑

SELECT [Authorizer Name], 
Sum([Q1A - CD # 1]) AS [Category 1], 
Sum([Q2A- CD # 2A] + [Q8A- CD # 2A] + [Q10A- CD # 2A] 
    + [CTS A accurate- CD # 2A] 
    + [e-correspondence A accurate- CD # 2A]) AS [Category 2], 
Sum([Q7A- CD # 2B] + [Q9A- CD # 2B] + [Q11A- CD # 2B] 
    + [CTS A procedures- CD # 2B] 
    + [e-correspondence A procedures- CD # 2B]) AS [Category 3], 
Sum([Q4A- CD # 3]) AS [Category 4], 
Sum([Q5A- CD # 4]) AS [Category 5], Sum([Q12A- CD # 5]) AS [Category 6] 
FROM [Review Results] 
WHERE [Review Results].[Authorizer Name] = 1 
GROUP BY [Review Results].[Authorizer Name];

该表当前是这样的：

Name    X1 X2A   X2B X2C X3A X3B X3C X4 X5 
Joe     1  5     0   1   1   5   6   0  0
Bob     2  7     0   2   1   4   2   1  9 
Billy   0  8     0   3   1   3   1   0  9

这就是我想要得到的：

Name     Joe                  Bob    Billy 
X1       1                     2         0 
X2 (sum of X2A/X2B/X2C) 6      9         11 
X3 (sum of X3A/X3B/X3C) 12     7         5 
X4       0                     1         0 
X5       0                     9         9

阅读 184

2021-03-17

共1个答案

一尘不染

首先创建一个UNION查询以规范化您的表，然后创建一个交叉表以显示数据：

SELECT [Name], "Cat 1" As Cat, [Cat 1] As CatVal FROM Table
UNION ALL
SELECT [Name], "Cat 2" As Cat, [Cat 2] As CatVal FROM Table
<...>

查询向导将指导您创建交叉表。

编辑评论

要规范样本数据表，您可以说：

SELECT [Name], "X1" As Cat, [X1] As CatVal FROM Table
UNION ALL
SELECT [Name], "X2" As Cat, Nz([X2A],0)+Nz([X2B],0)+Nz([X2C],0) As CatVal 
   FROM Table
UNION ALL
SELECT [Name], "X3" As Cat, Nz([X3A],0)+Nz([X3B],0)+Nz([X3C],0) As CatVal 
   FROM Table
UNION ALL
SELECT [Name], "X4" As Cat, [X4] As CatVal FROM Table
UNION ALL
SELECT [Name], "X5" As Cat, [X5] As CatVal FROM Table

假设联合查询是QueryX：

TRANSFORM First(QueryX.CatVal) AS FirstOfCatVal
SELECT QueryX.Cat
FROM QueryX
GROUP BY QueryX.Cat
PIVOT QueryX.Name;

2021-03-17