使用 LEFT JOIN/IS NULL

   SELECT DISTINCT
          i.data
     FROM IMAGE i
     JOIN USER_IMAGE ui ON ui.image_id = i.id
LEFT JOIN USER u ON u.id = ui.user_id
                AND u.user = ?
    WHERE u.id IS NULL

使用 NOT IN

SELECT DISTINCT
       i.data
  FROM IMAGE i
  JOIN USER_IMAGE ui ON ui.image_id = i.id
 WHERE ui.user_id NOT IN (SELECT u.id
                            FROM USER u
                           WHERE u.user = ?)

使用 NOT EXISTS

SELECT DISTINCT
       i.data
  FROM IMAGE i
  JOIN USER_IMAGE ui ON ui.image_id = i.id
 WHERE NOT EXISTS(SELECT NULL
                    FROM USER u
                   WHERE u.id = ui.user_id
                     AND u.user = ?)

表现：

的LEFT JOIN/IS NULL和NOT IN提供相当的性能-的NOT EXISTS是〜30％的效率低。
有关更多详细信息，请参见此内容。