一尘不染

重叠预订查询

sql

如果公寓只有一个预订,则以下查询有效。但是如果一间公寓预订不止一次,即使没有在请求的时间范围内可用,也会出现此公寓。

SELECT DISTINCT `apartment`.*
FROM `apartment` `apartment`
LEFT JOIN `booking` `booking` ON `apartment`.`uid` = `booking`.`apartment`
WHERE (
    NOT(
        ( `booking`.`start` <= '2018-07-23')
        AND
        ( `booking`.`end` >= '2018-07-21')
    )
)

有人可以帮我写正确的sql吗?

更新: 根据马特·雷恩斯(Matt
Raines)的提示,我在预订表上添加了带有公寓uid的野外公寓。我非常感谢您提出的任何建议,这些建议可以帮助我编写正确的SQL语句!

这里是 更新的 演示数据:

--
-- Table structure for table `apartment`
--
CREATE TABLE `apartment` (
  `uid` int(11) NOT NULL,
  `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
  `bookings` int(10) UNSIGNED NOT NULL DEFAULT '0'
)
--
-- Data for table `tx_apartments_domain_model_apartment`
--
INSERT INTO `apartment` (`uid`, `title`, `bookings`) VALUES
(1, 'Apartment 1', 2),
(2, 'Apartment 2', 1),
(3, 'Apartment 3', 1),
(4, 'Apartment 4', 1);

--
-- Table structure for table `booking`
--
CREATE TABLE `booking` (
  `uid` int(11) NOT NULL,
  `start` date DEFAULT '0000-00-00',
  `end` date DEFAULT '0000-00-00',
  `apartment` int(10) UNSIGNED NOT NULL DEFAULT '0'
)
--
-- Data for table `booking`
--
INSERT INTO `booking` (`uid`, `start`, `end`, `apartment`) VALUES
(1, '2018-07-18', '2018-07-20', 1),
(2, '2018-07-21', '2018-07-23', 1),
(3, '2018-07-18', '2018-07-20', 2);

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2021-03-17

共1个答案

一尘不染

考虑以下。

DROP TABLE IF EXISTS apartment;

CREATE TABLE apartment
(apartment_id SERIAL PRIMARY KEY
,apartment_name varchar(255) NOT NULL 
);

INSERT INTO apartment VALUES
(1, 'Apartment 1'),
(2, 'Apartment 2'),
(3, 'Apartment 3'),
(4, 'Apartment 4');

DROP TABLE IF EXISTS booking;

CREATE TABLE booking 
(booking_id SERIAL PRIMARY KEY
,start_date DATE NOT NULL
,end_date DATE NOT NULL
,apartment_id INT NOT NULL
);

INSERT INTO booking VALUES
(1, '2018-07-18', '2018-07-20', 1),
(2, '2018-07-21', '2018-07-23', 1),
(3, '2018-07-18', '2018-07-20', 2);



SELECT a.* 
  FROM apartment a 
  LEFT 
  JOIN booking b 
    ON b.apartment_id = a.apartment_id 
   AND b.start_date <= '2018-07-23' 
   AND b.end_date > '2018-07-21'
 WHERE b.booking_id IS NULL;
+--------------+----------------+
| apartment_id | apartment_name |
+--------------+----------------+
|            2 | Apartment 2    |
|            3 | Apartment 3    |
|            4 | Apartment 4    |
+--------------+----------------+

实际上,除非绑定在事务中,否则像这样的SELECT毫无意义,因为在您仍在检查可用性时,另一个用户可以轻松地进行预订。

2021-03-17