一尘不染

如何在数据库表中找到重复的条目?

sql

以下查询将显示在“书”表中重复的所有杜威十进制数:

SELECT dewey_number, 
 COUNT(dewey_number) AS NumOccurrences
FROM book
GROUP BY dewey_number
HAVING ( COUNT(dewey_number) > 1 )

但是,我想做的是让查询显示与重复条目关联的作者的姓名(“ book”表和“ author”表由“
author_id”连接)。换句话说,上面的查询将产生以下结果:

dewey_number | NumOccurrences
------------------------------
5000         | 2
9090         | 3

我希望显示的结果类似于以下内容:

author_last_name | dewey_number | NumOccurrences
-------------------------------------------------
Smith            | 5000         | 2
Jones            | 5000         | 2
Jackson          | 9090         | 3
Johnson          | 9090         | 3
Jeffers          | 9090         | 3

您能提供的任何帮助将不胜感激。而且,万一它起作用了,我使用的是Postgresql DB。

更新 :请注意,“ book”表中没有“ author_last_name”。


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2021-03-17

共1个答案

一尘不染

嵌套查询可以完成这项工作。

SELECT author_last_name, dewey_number, NumOccurrences
FROM author INNER JOIN
     ( SELECT author_id, dewey_number,  COUNT(dewey_number) AS NumOccurrences
        FROM book
        GROUP BY author_id, dewey_number
        HAVING ( COUNT(dewey_number) > 1 ) ) AS duplicates
ON author.id = duplicates.author_id

(我不知道这是否是实现您想要的最快的方法。)

更新:这是我的数据

SELECT * FROM author;
 id | author_last_name 
----+------------------
  1 | Fowler
  2 | Knuth
  3 | Lang

SELECT * FROM book;
 id | author_id | dewey_number |         title          
----+-----------+--------------+------------------------
  1 |         1 |          600 | Refactoring
  2 |         1 |          600 | Refactoring
  3 |         1 |          600 | Analysis Patterns
  4 |         2 |          600 | TAOCP vol. 1
  5 |         2 |          600 | TAOCP vol. 1
  6 |         2 |          600 | TAOCP vol. 2
  7 |         3 |          500 | Algebra
  8 |         3 |          500 | Undergraduate Analysis
  9 |         1 |          600 | Refactoring
 10 |         2 |          500 | Concrete Mathematics
 11 |         2 |          500 | Concrete Mathematics
 12 |         2 |          500 | Concrete Mathematics

这是上述查询的结果:

 author_last_name | dewey_number | numoccurrences 
------------------+--------------+----------------
 Fowler           |          600 |              4
 Knuth            |          600 |              3
 Knuth            |          500 |              3
 Lang             |          500 |              2
2021-03-17