我正在尝试对字符串列( 包含数字 )进行排序。
// SELECT `name` FROM `mytable` ORDER BY `name` ASC +----------+ +-- name --+ +----------+ +-- a 1 ---+ +-- a 12 --+ +-- a 2 ---+ +-- a 3 ---+
您会看到Mysql的自然排序算法放在a 12后面a 1( 对于大多数应用程序来说都可以 ),但是我有独特的需求,因此我希望结果应该像这样排序。
a 12
a 1
+----------+ +-- name --+ +----------+ +-- a 1 ---+ +-- a 2 ---+ +-- a 3 ---+ +-- a 12 --+
仅使用SQL 是否可能,或者我必须在应用程序级别操纵结果集?
继续 假设 它始终为WORD_space_NUMBER,这应该可行:
SELECT * FROM table ORDER BY CAST(SUBSTRING(column,LOCATE(' ',column)+1) AS SIGNED)
使用POSITION查找空间,使用SUBSTRING捕获其后的数字,然后使用CAST使其具有可比较的值。
如果该列有另一种模式,请告诉我,我将尝试设计一种更好的解决方法。
编辑 证明有效:
mysql> INSERT INTO t (st) VALUES ('a 1'),('a 12'),('a 6'),('a 11'); Query OK, 4 rows affected (0.00 sec) Records: 4 Duplicates: 0 Warnings: 0 mysql> SELECT * FROM t ORDER BY st; +----+------+ | id | st | +----+------+ | 1 | a 1 | | 4 | a 11 | | 2 | a 12 | | 3 | a 6 | +----+------+ 4 rows in set (0.00 sec) mysql> SELECT * FROM t ORDER BY CAST(SUBSTRING(st,LOCATE(' ',st)+1) AS SIGNED); +----+------+ | id | st | +----+------+ | 1 | a 1 | | 3 | a 6 | | 4 | a 11 | | 2 | a 12 | +----+------+ mysql> INSERT INTO t (st) VALUES ('b 1'),('b 12'),('b 6'),('b 11'); Query OK, 4 rows affected (0.00 sec) Records: 4 Duplicates: 0 Warnings: 0 mysql> SELECT * FROM t ORDER BY CAST(SUBSTRING(st,LOCATE(' ',st)+1) AS SIGNED); +----+------+ | id | st | +----+------+ | 1 | a 1 | | 5 | b 1 | | 3 | a 6 | | 7 | b 6 | | 4 | a 11 | | 8 | b 11 | | 2 | a 12 | | 6 | b 12 | +----+------+ 8 rows in set (0.00 sec) mysql> SELECT * FROM t ORDER BY LEFT(st,LOCATE(' ',st)), CAST(SUBSTRING(st,LOCATE(' ',st)+1) AS SIGNED); +----+------+ | id | st | +----+------+ | 1 | a 1 | | 3 | a 6 | | 4 | a 11 | | 2 | a 12 | | 5 | b 1 | | 7 | b 6 | | 8 | b 11 | | 6 | b 12 | +----+------+ 8 rows in set (0.00 sec)
忽略我的la脚表/列名,但会给我正确的结果。还走得更远,添加了双重排序功能,以数字打破字母前缀。
编辑 SUBSTRING_INDEX将使其更具可读性。
SUBSTRING_INDEX
ORDER BY SUBSTRING_INDEX(st, " ", 1) ASC, CAST(SUBSTRING_INDEX(st, " ", -1) AS SIGNED)