SQL Server 2000中的Row

一尘不染

SQL Server 2000中的Row_Number模拟

sql

我有一个示例输入表

Declare  @input TABLE(Name VARCHAR(8))
INSERT INTO @input(Name)  values('Aryan') 
INSERT INTO @input(Name)  values('Aryan') 
INSERT INTO @input(Name)  values('Joseph') 
INSERT INTO @input(Name)  values('Vicky') 
INSERT INTO @input(Name)  values('Jaesmin') 
INSERT INTO @input(Name)  values('Aryan') 
INSERT INTO @input(Name)  values('Jaesmin') 
INSERT INTO @input(Name)  values('Vicky') 
INSERT INTO @input(Name)  values('Padukon') 
INSERT INTO @input(Name)  values('Aryan') 
INSERT INTO @input(Name)  values('Jaesmin') 
INSERT INTO @input(Name)  values('Vick') 
INSERT INTO @input(Name)  values('Padukon') 
INSERT INTO @input(Name)  values('Joseph') 
INSERT INTO @input(Name)  values('Marya') 
INSERT INTO @input(Name)  values('Vicky')

我也有一个理货桌子如下

declare @t table(n int)
insert into @t select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all select 8 union all
select 9 union all select 10 union all select 11 union all
select 12 union all select 13 union all select 14 union all
select 15 union all select 16 union all select 17 union all
select 18 union all select 19 union all select 20

在Sql Server 2005中，如果我这样做

 Select rn, name from (
    select ROW_NUMBER()over (order by Name) as rn , * from @input) x
    where rn % 2 <> 0

我得到的输出为

rn  name
1   Aryan
3   Aryan
5   Jaesmin
7   Jaesmin
9   Joseph
11  Padukon
13  Vick
15  Vicky

我只能使用Sql Server2000。如何获得相同的输出？

我尝试过

SELECT name, (SELECT COUNT(*) FROM @input AS i2 WHERE i2.Name <= i1.Name) As rn
FROM @input AS i1

但是输出错误

name    rn
Aryan   4
Aryan   4
Joseph  9
Vicky   16
Jaesmin 7
Aryan   4
Jaesmin 7
Vicky   16
Padukon 12
Aryan   4
Jaesmin 7
Vick    13
Padukon 12
Joseph  9
Marya   10
Vicky   16

阅读 147

2021-05-05

共1个答案

一尘不染

使用此查询：

SELECT t1.name, t.n
FROM
(
    SELECT a.name, a.c, (SELECT COUNT(*) FROM @input AS i2 WHERE i2.Name <= a.Name) [rn]
    FROM
    (
        SELECT i.name, count(*) c
        FROM @input i
        GROUP BY i.name
    )a
)t1
JOIN @t t ON t.n <= t1.rn
WHERE t.n > t1.rn - t1.c

它产生所需的输出：

name     n
-------- -----------
Aryan    1
Aryan    2
Aryan    3
Aryan    4
Jaesmin  5
Jaesmin  6
Jaesmin  7
Joseph   8
Joseph   9
Marya    10
Padukon  11
Padukon  12
Vick     13
Vicky    14
Vicky    15
Vicky    16

2021-05-05