PHP MYSQL INSERT帮助没有错误

一尘不染

PHP MYSQL INSERT帮助没有错误

sql

即时通讯试图抄袭我的添加视频提交表单以更新另一个mysql表，以跟踪提交者发布了哪些视频链接。我试图通过使用MAX（）获取插入到提交表中的最后一个videoId来插入视频ID，而用户名将仅来自：submitter，并且postdOn使用now（）来获取时间戳。使用提交表单后，没有数据输入到adminposts表中，并且没有收到任何错误。谢谢您的帮助。

<?php


    require_once '../connection.php';

    $sql = "INSERT INTO videoinfo
            (submitter,videoTitle,channelName,videoLink,videoLength)
            VALUES(:submitter,:videoTitle,:channelName,:videoLink,:videoLength)";

    $stmt = $dataconn -> prepare($sql); 
    $stmt -> execute(array(":submitter"=> $_POST['submitter'],
    ":videoTitle"=> $_POST['videoTitle'],
    ":channelName"=> $_POST['channelName'],
    ":videoLink"=> $_POST['videoLink'],
    ":videoLength"=> $_POST['videoLength']));

    $sql = "SELECT MAX(videoId) FROM videoinfo";
    $stmt = $dataconn->prepare($sql);   
    $stmt -> execute(array());
    $record = $stmt->fetch();
    $videoID = $record['videoId'];

    $username = $_POST['submitter'];
    $postedOn = now();

    $sql = "INSERT INTO adminposts
            (videoId,username,postedOn)
            VALUES(:videoId,:username,postedOn = now())";
    $stmt = $dataconn -> prepare($sql);
    $stmt -> execute(array(":videoId"=> $videoID,
                            ":username"=> $username));





    echo "<h3>Video has been successfully added!";

    include 'adminmain.php'
    ?>

更新的代码

    $sql = "SELECT MAX(videoId) AS videoId FROM videoinfo";
    $stmt = $dataconn->prepare($sql);   
    $stmt -> execute(array());
    $record = $stmt->fetch();
    $videoID = $record['videoId'];
    var_dump($videoID);
    $username = $_POST['submitter'];
    $postedOn = now();

    $sql = "INSERT INTO adminposts
            (videoId,username,postedOn)
            VALUES(:videoId,:username,$postedOn)";
    $stmt = $dataconn -> prepare($sql);
    $stmt -> execute(array(":videoId"=> $videoID,
                            ":username"=> $username));
$stmt->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

阅读 93

2021-05-16

共1个答案

一尘不染

以下为我工作：

我必须指出，您不能将其$postedOn = now();用作发布当前时间/日期的变量。需要将其输入为VALUES

IE： VALUES(:videoId,:username,NOW())";

请注意，我用作$pdo连接变量。

<?php

$mysql_hostname = 'xxx';
$mysql_username = 'xxx';
$mysql_password = 'xxx';
$mysql_dbname = 'xxx';

try {

$pdo= new PDO("mysql:host=$mysql_hostname;dbname=$mysql_dbname", $mysql_username, $mysql_password); 
     $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (PDOException $e) {
     exit( $e->getMessage() );
}

$sql = "SELECT MAX(videoId) AS videoId FROM videoinfo";

$stmt = $pdo->prepare($sql);   
$stmt -> execute(array());
$record = $stmt->fetch();
$videoID = $record['videoId'];

// var_dump($videoID);

$username = $_POST['submitter'];

try {
$sql = "INSERT INTO adminposts
        (videoId,username,postedOn)
        VALUES(:videoId,:username,NOW())";
$stmt = $pdo -> prepare($sql);
$stmt -> execute(array(":videoId"=> $videoID,":username"=> $username));
}

catch(PDOException $e){
// $result = "Sorry, an error occurred while editing the database.";

// will print a message of the actual error should there be one
print $e->getMessage();

    }

2021-05-16