如何使用MySQL对连续范围进行分组

一尘不染

如何使用MySQL对连续范围进行分组

mysql

我有一个包含类别，日期和费率的表。每个类别在不同日期可以具有不同的费率，一个类别在给定日期只能具有一个费率。

Id        CatId    Date        Rate 
------  ------   ------------   ---------
000001      12   2009-07-07     1
000002      12   2009-07-08     1
000003      12   2009-07-09     1
000004      12   2009-07-10     2
000005      12   2009-07-15     1
000006      12   2009-07-16     1
000007      13   2009-07-08     1
000008      13   2009-07-09     1
000009      14   2009-07-07     2
000010      14   2009-07-08     1
000010      14   2009-07-10     1

唯一索引（类别，日期，费率）我希望针对每个类别将所有连续的日期范围归为一组，并仅保留范围的开始和结束。对于前面的示例，我们将有：

CatId    Begin          End            Rate 
------   ------------   ------------   ---------
12        2009-07-07    2009-07-09     1
12        2009-07-10    2009-07-10     2
12        2009-07-15    2009-07-16     1  
13        2009-07-08    2009-07-09     1  
14        2009-07-07    2009-07-07     2
14        2009-07-08    2009-07-08     1
14        2009-07-10    2009-07-10     1

我在论坛中找到了一个类似的解决方案，但并未完全给出结果

WITH    q AS
        (
        SELECT  *,
                ROW_NUMBER() OVER (PARTITION BY CatId, Rate ORDER BY [Date]) AS rnd,
                ROW_NUMBER() OVER (PARTITION BY CatId ORDER BY [Date]) AS rn
        FROM    my_table
        )
SELECT  CatId AS catidd, MIN([Date]) as beginn, MAX([Date])as endd, Rate
FROM    q
GROUP BY  CatId, rnd - rn, Rate

请参见SQL FIDDLE 如何在mysql中做同样的事情？请帮忙！

阅读 609

2020-05-17

共1个答案

一尘不染

MySQL不支持解析功能，但是您可以使用用户定义的变量来模仿这种行为：

SELECT   CatID, Begin, MAX(Date) AS End, Rate
FROM (
  SELECT   my_table.*,
           @f:=CONVERT(
             IF(@c<=>CatId AND @r<=>Rate AND DATEDIFF(Date, @d)=1, @f, Date), DATE
           ) AS Begin,
           @c:=CatId, @d:=Date, @r:=Rate
  FROM     my_table JOIN (SELECT @c:=NULL) AS init
  ORDER BY CatId, Rate, Date
) AS t
GROUP BY CatID, Begin, Rate

在sqlfiddle上看到它。

2020-05-17