给定此表：

create table test (
    name text primary key
);

我需要编写一个plpgsql函数，其变量名与主键名冲突，必须在on conflict子句中使用该主键名：

create or replace function func(
    name text                               -- this variable name...
) returns void language plpgsql as 
$$
begin 
    insert into test (name) values (name) 
    on conflict (name) do update            -- ...conflicts with this line
    set name = func.name; 
end; 
$$;

这将进行编译，但随后会抛出一个含糊的列引用：

select * from func('one');
ERROR:  column reference "name" is ambiguous
LINE 2:     on conflict (name) do update 
                        ^
DETAIL:  It could refer to either a PL/pgSQL variable or a table column.
QUERY:  insert into test (name) values (name) 
    on conflict (name) do update 
    set name = func.name
CONTEXT:  PL/pgSQL function func(text) line 3 at SQL statement

我尝试将完整的列名指定为on conflict (test.name)不编译，或((test.name))不编译：

create or replace function func(
    name text
) returns void language plpgsql as 
$$
begin 
    insert into test (name) values (name) 
    on conflict ((test.name)) do            -- this fails too
    update set name = func.name; 
end; 
$$;

但是它也失败了：

select * from func('two');
ERROR:  invalid reference to FROM-clause entry for table "test"
LINE 2:     on conflict ((test.name)) do 
                          ^
HINT:  There is an entry for table "test", but it cannot be referenced from this part of the query.
QUERY:  insert into test (name) values (name) 
    on conflict ((test.name)) do 
    update set name = func.name
CONTEXT:  PL/pgSQL function func(text) line 3 at SQL statement

有解决方案吗？

编辑：我找到了一种解决方法：

on conflict on constraint test_pkey do update

test_pkey表名加在哪里_pkey。我不知道这有多可靠。我仍然想改为指定列名。