我正在尝试使用 go 将图像从我的计算机上传到网站。通常,我使用 bash 脚本向服务器发送文件和密钥:
curl -F "image"=@"IMAGEFILE" -F "key"="KEY" URL
它工作正常,但我正在尝试将此请求转换为我的 golang 程序。
http://matt.aimonetti.net/posts/2013/07/01/golang-multipart-file-upload-example/
我尝试了这个链接和许多其他链接,但是,对于我尝试的每个代码,来自服务器的响应是“没有发送图像”,我不知道为什么。如果有人知道上面的例子发生了什么。
这是一些示例代码。
简而言之,您需要使用该mime/multipart包来构建表单。
mime/multipart
package main import ( "bytes" "fmt" "io" "mime/multipart" "net/http" "net/http/httptest" "net/http/httputil" "os" "strings" ) func main() { var client *http.Client var remoteURL string { //setup a mocked http client. ts := httptest.NewTLSServer(http.HandlerFunc(func(w http.ResponseWriter, r *http.Request) { b, err := httputil.DumpRequest(r, true) if err != nil { panic(err) } fmt.Printf("%s", b) })) defer ts.Close() client = ts.Client() remoteURL = ts.URL } //prepare the reader instances to encode values := map[string]io.Reader{ "file": mustOpen("main.go"), // lets assume its this file "other": strings.NewReader("hello world!"), } err := Upload(client, remoteURL, values) if err != nil { panic(err) } } func Upload(client *http.Client, url string, values map[string]io.Reader) (err error) { // Prepare a form that you will submit to that URL. var b bytes.Buffer w := multipart.NewWriter(&b) for key, r := range values { var fw io.Writer if x, ok := r.(io.Closer); ok { defer x.Close() } // Add an image file if x, ok := r.(*os.File); ok { if fw, err = w.CreateFormFile(key, x.Name()); err != nil { return } } else { // Add other fields if fw, err = w.CreateFormField(key); err != nil { return } } if _, err = io.Copy(fw, r); err != nil { return err } } // Don't forget to close the multipart writer. // If you don't close it, your request will be missing the terminating boundary. w.Close() // Now that you have a form, you can submit it to your handler. req, err := http.NewRequest("POST", url, &b) if err != nil { return } // Don't forget to set the content type, this will contain the boundary. req.Header.Set("Content-Type", w.FormDataContentType()) // Submit the request res, err := client.Do(req) if err != nil { return } // Check the response if res.StatusCode != http.StatusOK { err = fmt.Errorf("bad status: %s", res.Status) } return } func mustOpen(f string) *os.File { r, err := os.Open(f) if err != nil { panic(err) } return r }