有一个简单的技巧可以将连续的条目折叠成一个组。如果按（row_number-entry）进行分组，则连续的条目将在同一组中结束。这是一个演示我的意思的示例：

查询 ：

SELECT phonenum, @curRow := @curRow + 1 AS row_number, phonenum - @curRow
from phonenums p
join (SELECT @curRow := 0) r

结果 ：

|    PHONENUM | ROW_NUMBER | PHONENUM - @CURROW |
-------------------------------------------------
| 27100070000 |          1 |        27100069999 |
| 27100070001 |          2 |        27100069999 |
| 27100070002 |          3 |        27100069999 |
| 27100070003 |          4 |        27100069999 |
| 27100070004 |          5 |        27100069999 |
| 27100070005 |          6 |        27100069999 |
| 27100070008 |          7 |        27100070001 |
| 27100070009 |          8 |        27100070001 |
| 27100070012 |          9 |        27100070003 |
| 27100070015 |         10 |        27100070005 |
| 27100070016 |         11 |        27100070005 |
| 27100070040 |         12 |        27100070028 |

请注意，连续的条目如何都具有相同的值PHONENUM - @CURROW。如果我们在该列上进行分组，然后选择每个组的最小值和最大值，那么您将获得摘要（一个例外：如果需要，可以将NULLSTART = END
替换为END值）：

查询 ：

select min(phonenum), max(phonenum) from
(
  SELECT phonenum, @curRow := @curRow + 1 AS row_number
  from phonenums p
  join (SELECT @curRow := 0) r
) p
group by phonenum - row_number

结果 ：

| MIN(PHONENUM) | MAX(PHONENUM) |
---------------------------------
|   27100070000 |   27100070005 |
|   27100070008 |   27100070009 |
|   27100070012 |   27100070012 |
|   27100070015 |   27100070016 |
|   27100070040 |   27100070040 |

演示：http ://www.sqlfiddle.com/#!2/
59b04/5