我使用一些序列化的强类型表达式,以允许我的UI代码具有强类型的排序和搜索表达式。这些是类型,Expression<Func<TModel,TProperty>>并按以下方式使用:SortOption.Field = (p => p.FirstName);。对于这个简单的案例,我已经做到了这一点。
Expression<Func<TModel,TProperty>>
SortOption.Field = (p => p.FirstName);
实际上,我用于解析“ FirstName”属性的代码实际上正在重用我们使用的第三方产品中的某些现有功能,并且效果很好,直到我们开始使用深度嵌套的properties(SortOption.Field = (p => p.Address.State.Abbreviation);)。对于支持深度嵌套的属性,此代码有一些非常不同的假设。
SortOption.Field = (p => p.Address.State.Abbreviation);
至于这段代码的作用,我并不太了解,而不是更改该代码,我认为我应该从头开始编写此功能。但是,我不知道这样做的 好 方法。我怀疑我们可以做一些比做ToString()和执行字符串解析更好的事情。那么,什么是处理琐碎而又深层嵌套的案件的好方法呢?
要求:
p => p.FirstName
"FirstName"
p => p.Address.State.Abbreviation
"Address.State.Abbreviation"
尽管对我的问题的回答并不重要,但我怀疑我的序列化/反序列化代码可能对将来发现此问题的其他人有用,因此如下。同样,此代码对这个问题并不重要- 我只是认为它可能对某人有帮助。请注意,这DynamicExpression.ParseLambda是来自Dynamic LINQ的东西,Property.PropertyToString()它是关于这个问题的。
DynamicExpression.ParseLambda
Property.PropertyToString()
/// <summary> /// This defines a framework to pass, across serialized tiers, sorting logic to be performed. /// </summary> /// <typeparam name="TModel">This is the object type that you are filtering.</typeparam> /// <typeparam name="TProperty">This is the property on the object that you are filtering.</typeparam> [Serializable] public class SortOption<TModel, TProperty> : ISerializable where TModel : class { /// <summary> /// Convenience constructor. /// </summary> /// <param name="property">The property to sort.</param> /// <param name="isAscending">Indicates if the sorting should be ascending or descending</param> /// <param name="priority">Indicates the sorting priority where 0 is a higher priority than 10.</param> public SortOption(Expression<Func<TModel, TProperty>> property, bool isAscending = true, int priority = 0) { Property = property; IsAscending = isAscending; Priority = priority; } /// <summary> /// Default Constructor. /// </summary> public SortOption() : this(null) { } /// <summary> /// This is the field on the object to filter. /// </summary> public Expression<Func<TModel, TProperty>> Property { get; set; } /// <summary> /// This indicates if the sorting should be ascending or descending. /// </summary> public bool IsAscending { get; set; } /// <summary> /// This indicates the sorting priority where 0 is a higher priority than 10. /// </summary> public int Priority { get; set; } #region Implementation of ISerializable /// <summary> /// This is the constructor called when deserializing a SortOption. /// </summary> protected SortOption(SerializationInfo info, StreamingContext context) { IsAscending = info.GetBoolean("IsAscending"); Priority = info.GetInt32("Priority"); // We just persisted this by the PropertyName. So let's rebuild the Lambda Expression from that. Property = DynamicExpression.ParseLambda<TModel, TProperty>(info.GetString("Property"), default(TModel), default(TProperty)); } /// <summary> /// Populates a <see cref="T:System.Runtime.Serialization.SerializationInfo"/> with the data needed to serialize the target object. /// </summary> /// <param name="info">The <see cref="T:System.Runtime.Serialization.SerializationInfo"/> to populate with data. </param> /// <param name="context">The destination (see <see cref="T:System.Runtime.Serialization.StreamingContext"/>) for this serialization. </param> public void GetObjectData(SerializationInfo info, StreamingContext context) { // Just stick the property name in there. We'll rebuild the expression based on that on the other end. info.AddValue("Property", Property.PropertyToString()); info.AddValue("IsAscending", IsAscending); info.AddValue("Priority", Priority); } #endregion }
诀窍是:这种形式的任何表达方式…
obj => obj.A.B.C // etc.
…实际上只是一堆嵌套MemberExpression对象。
MemberExpression
首先,您必须:
MemberExpression: obj.A.B.C Expression: obj.A.B // MemberExpression Member: C
评估Expression上面 _的MemberExpression_为您提供:
Expression
MemberExpression: obj.A.B Expression: obj.A // MemberExpression Member: B
最后,以上 这 (在“顶部”),你必须:
MemberExpression: obj.A Expression: obj // note: not a MemberExpression Member: A
因此,似乎很明显,解决此问题的方法是通过检查up 的Expression属性,MemberExpression直到不再成为a本身为止MemberExpression。
更新 :看来您的问题有一个额外的旋转。可能您有一些lambda 看起来 像Func<T, int>…
Func<T, int>
p => p.Age
…但 实际上是 一个Func<T, object>; 在这种情况下,编译器会将上面的表达式转换为:
Func<T, object>
p => Convert(p.Age)
实际上,针对此问题进行调整并不像看起来那样困难。查看我的更新代码,了解一种处理它的方法。请注意,通过抽象化用于MemberExpression脱离其自身方法(TryFindMemberExpression)的代码,该方法可以使GetFullPropertyName方法保持相当干净,并允许您将来添加其他检查- 如果也许您发现自己面对的是 新 环境,最初并没有考虑-无需花费太多代码。
TryFindMemberExpression
GetFullPropertyName
举例说明:这段代码对我有用。
// code adjusted to prevent horizontal overflow static string GetFullPropertyName<T, TProperty> (Expression<Func<T, TProperty>> exp) { MemberExpression memberExp; if (!TryFindMemberExpression(exp.Body, out memberExp)) return string.Empty; var memberNames = new Stack<string>(); do { memberNames.Push(memberExp.Member.Name); } while (TryFindMemberExpression(memberExp.Expression, out memberExp)); return string.Join(".", memberNames.ToArray()); } // code adjusted to prevent horizontal overflow private static bool TryFindMemberExpression (Expression exp, out MemberExpression memberExp) { memberExp = exp as MemberExpression; if (memberExp != null) { // heyo! that was easy enough return true; } // if the compiler created an automatic conversion, // it'll look something like... // obj => Convert(obj.Property) [e.g., int -> object] // OR: // obj => ConvertChecked(obj.Property) [e.g., int -> long] // ...which are the cases checked in IsConversion if (IsConversion(exp) && exp is UnaryExpression) { memberExp = ((UnaryExpression)exp).Operand as MemberExpression; if (memberExp != null) { return true; } } return false; } private static bool IsConversion(Expression exp) { return ( exp.NodeType == ExpressionType.Convert || exp.NodeType == ExpressionType.ConvertChecked ); }
用法:
Expression<Func<Person, string>> simpleExp = p => p.FirstName; Expression<Func<Person, string>> complexExp = p => p.Address.State.Abbreviation; Expression<Func<Person, object>> ageExp = p => p.Age; Console.WriteLine(GetFullPropertyName(simpleExp)); Console.WriteLine(GetFullPropertyName(complexExp)); Console.WriteLine(GetFullPropertyName(ageExp));
输出:
FirstName Address.State.Abbreviation Age