只需将其包装在jar中的任何位置即可。不过，你必须记住一件事-在使用DLL之前，你需要先从JAR中提取这些DLL，然后将其转储到硬盘上的某个位置，否则你将无法加载这些DLL。

所以基本上-我为客户端做了JNI项目，我将在战争中使用这种打包的jar。但是-在运行任何本机方法之前，我将获得DLL作为资源并将其写入光盘到temp目录中。然后，我将运行常规的初始化代码，在该代码中，我的DLL设置为与我刚刚写入DLL相同的位置

哦，以防万一：将dll或任何其他文件包装到jar中没有什么特别的。就像把东西包装成拉链

这是我刚挖出的一些代码

public class Foo {
private static final String LIB_BIN = "/lib-bin/";
private final static Log logger = LogFactory.getLog(ACWrapper.class);
private final static String ACWRAPPER = "acwrapper";
private final static String AAMAPI = "aamapi51";
private final static String LIBEAU = "libeay32";

static {
    logger.info("Loading DLL");
    try {
        System.loadLibrary(ACWRAPPER);
        logger.info("DLL is loaded from memory");
    } catch (UnsatisfiedLinkError e) {
        loadFromJar();
    }
}

/**
 * When packaged into JAR extracts DLLs, places these into
 */
private static void loadFromJar() {
    // we need to put both DLLs to temp dir
    String path = "AC_" + new Date().getTime();
    loadLib(path, ACWRAPPER);
    loadLib(path, AAMAPI);
    loadLib(path, LIBEAU);
}

/**
 * Puts library to temp dir and loads to memory
 */
private static void loadLib(String path, String name) {
    name = name + ".dll";
    try {
        // have to use a stream
        InputStream in = ACWrapper.class.getResourceAsStream(LIB_BIN + name);
        // always write to different location
        File fileOut = new File(System.getProperty("java.io.tmpdir") + "/" + path + LIB_BIN + name);
        logger.info("Writing dll to: " + fileOut.getAbsolutePath());
        OutputStream out = FileUtils.openOutputStream(fileOut);
        IOUtils.copy(in, out);
        in.close();
        out.close();
        System.load(fileOut.toString());
    } catch (Exception e) {
        throw new ACCoreException("Failed to load required DLL", e);
    }
}
    // blah-blah - more stuff
}