所以我有一个脚本,可以返回特定月份和年份中的星期数。我该如何从该月开始的某一天,确定是该月的第1,2,3,4或5周的一部分?
我尝试过的最令人沮丧的事情-就是这里!
<?php /** * Returns the amount of weeks into the month a date is * @param $date a YYYY-MM-DD formatted date * @param $rollover The day on which the week rolls over */ function getWeeks($date, $rollover) { $cut = substr($date, 0, 8); $daylen = 86400; $timestamp = strtotime($date); $first = strtotime($cut . "00"); $elapsed = ($timestamp - $first) / $daylen; $weeks = 1; for ($i = 1; $i <= $elapsed; $i++) { $dayfind = $cut . (strlen($i) < 2 ? '0' . $i : $i); $daytimestamp = strtotime($dayfind); $day = strtolower(date("l", $daytimestamp)); if($day == strtolower($rollover)) $weeks ++; } return $weeks; } // echo getWeeks("2011-06-11", "sunday"); //outputs 2, for the second week of the month ?>