我一直在获取要使用mysqli返回的行数方面遇到麻烦。即使确实有一些结果,我每次都会得到0。
if($stmt = $mysqli->prepare("SELECT id, title, visible, parent_id FROM content WHERE parent_id = ? ORDER BY page_order ASC;")){ $stmt->bind_param('s', $data->id); $stmt->execute(); $num_of_rows = $stmt->num_rows; $stmt->bind_result($child_id, $child_title, $child_visible, $child_parent); while($stmt->fetch()){ //code } echo($num_of_rows); $stmt->close(); }
为什么没有显示正确的数字?
您需要先调用MySqli_Stmt::store_result()num_rows查找:
MySqli_Stmt::store_result()
if($stmt = $mysqli->prepare("SELECT id, title, visible, parent_id FROM content WHERE parent_id = ? ORDER BY page_order ASC;")){ $stmt->bind_param('s', $data->id); $stmt->execute(); $stmt->store_result(); <-- This needs to be called here! $num_of_rows = $stmt->num_rows; $stmt->bind_result($child_id, $child_title, $child_visible, $child_parent); while($stmt->fetch()){ //code } echo($num_of_rows); $stmt->close(); }
请参阅文档MySQLi_Stmt->num_rows,该文档显示在页面顶部附近(在主要说明区域中)…
MySQLi_Stmt->num_rows