一尘不染

Java将整数转换为字节数组

java

将转换Integer为的快速方法是Byte Array什么?

例如 0xAABBCCDD => {AA, BB, CC, DD}


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2020-03-09

共1个答案

一尘不染

看看ByteBuffer类。

ByteBuffer b = ByteBuffer.allocate(4);
//b.order(ByteOrder.BIG_ENDIAN); // optional, the initial order of a byte buffer is always BIG_ENDIAN.
b.putInt(0xAABBCCDD);

byte[] result = b.array();

设置字节顺序保证了result[0] == 0xAAresult[1] == 0xBBresult[2] == 0xCCresult[3] == 0xDD

或者,你可以手动执行以下操作:

byte[] toBytes(int i)
{
  byte[] result = new byte[4];

  result[0] = (byte) (i >> 24);
  result[1] = (byte) (i >> 16);
  result[2] = (byte) (i >> 8);
  result[3] = (byte) (i /*>> 0*/);

  return result;
}

ByteBuffer班是专为尽管这样的脏手任务。实际上,私有java.nio.Bits定义了以下辅助方法ByteBuffer.putInt()

private static byte int3(int x) { return (byte)(x >> 24); }
private static byte int2(int x) { return (byte)(x >> 16); }
private static byte int1(int x) { return (byte)(x >>  8); }
private static byte int0(int x) { return (byte)(x >>  0); }
2020-03-09