例如，让我们使用一些简单的数据集

+---------+------+------+------------+
| name    | age  | sex  | position   |
+---------+------+------+------------+
| Antony  |   34 | M    | programmer |
| Sally   |   30 | F    | manager    |
| Matthew |   28 | M    | designer   |
+---------+------+------+------------+

我们想要得到的是这样组织的数组

Array
(
  [Antony] => Array
    (
      [age] => 34
      [sex] => M
      [position] => programmer
    )

  [Sally] => Array
    (
      [age] => 30
      [sex] => F
      [position] => manager
    )

  [Matthew] => Array
    (
      [age] => 28
      [sex] => M
      [position] => designer
    )
)

作为粗略的近似，我们可以使用

$pdo->query('SELECT * FROM employee')->fetchAll(PDO::FETCH_GROUP|PDO::FETCH_ASSOC);

但是结果是我们有不必要的嵌套级别

Array
(
    [Antony] => Array
        (
            [0] => Array
                (
                    [age] => 34
                    [sex] => M
                    [position] => programmer
                )

        )

    [Sally] => Array
        (
            [0] => Array
                (
                    [age] => 30
                    [sex] => F
                    [position] => manager
                )

        )

    [Matthew] => Array
        (
            [0] => Array
                (
                    [age] => 28
                    [sex] => M
                    [position] => designer
                )

        )

)

我试图通过使用回调函数摆脱这种不必要的嵌套级别

$stmt->fetchAll(PDO::FETCH_GROUP|PDO::FETCH_ASSOC|PDO::FETCH_FUNC, 'current');

但是由于某些原因它没有通过

Array
  (
   [0] => Array
    (
        [age] => 34
        [sex] => M
        [position] => programmer
    )
  )

但是只是一堆标量34, 'M', 'programmer'来回调函数:(

您可以使用回调等功能查看它

function what_do_you_pass_me() {

  $numargs = func_num_args();
  $arg_list = func_get_args();
  for ($i = 0; $i < $numargs; $i++) {
    echo "Argument $i is: " . $arg_list[$i] . "\n";
  };
  echo "\n\n";
};

那么有没有一种方法可以在PDO::FETCH_*不array_map('current', $result)获取结果后使用模式的情况下获得所需的结果集？