这是我提出的解决方案。它基于蒂姆的建议，即比较后续角色的顺序。一些结果：

• jonas / jonax : 0.8
• jonas / sjona : 0.68
• jonas / sjonas : 0.66
• jonas / asjon : 0.52
• jonas / xxjon : 0.36

我确定我并不完美，并且可以对其进行优化，但是尽管如此，它似乎仍会产生我所追求的结果。一个弱点是，当字符串长度不同时，当字符串长度不同时，它会产生不同的结果。值被交换…

static public function string_compare($str_a, $str_b) 
{
    $length = strlen($str_a);
    $length_b = strlen($str_b);

    $i = 0;
    $segmentcount = 0;
    $segmentsinfo = array();
    $segment = '';
    while ($i < $length) 
    {
        $char = substr($str_a, $i, 1);
        if (strpos($str_b, $char) !== FALSE) 
        {               
            $segment = $segment.$char;
            if (strpos($str_b, $segment) !== FALSE) 
            {
                $segmentpos_a = $i - strlen($segment) + 1;
                $segmentpos_b = strpos($str_b, $segment);
                $positiondiff = abs($segmentpos_a - $segmentpos_b);
                $posfactor = ($length - $positiondiff) / $length_b; // <-- ?
                $lengthfactor = strlen($segment)/$length;
                $segmentsinfo[$segmentcount] = array( 'segment' => $segment, 'score' => ($posfactor * $lengthfactor));
            } 
            else 
            {
                $segment = '';
                $i--;
                $segmentcount++;
            } 
        } 
        else 
        {
            $segment = '';
            $segmentcount++;
        }
        $i++;
    }

    // PHP 5.3 lambda in array_map      
    $totalscore = array_sum(array_map(function($v) { return $v['score'];  }, $segmentsinfo));
    return $totalscore;     
}