我正在使用最新版本的Spring Boot通过Restful Web Service读取示例JSON …
这是我的pom.xml:
<?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <modelVersion>4.0.0</modelVersion> <groupId>org.springframework</groupId> <artifactId>myservice</artifactId> <version>0.1.0</version> <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>1.2.2.RELEASE</version> </parent> <properties> <java.version>1.7</java.version> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding> </properties> <dependencies> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-web</artifactId> </dependency> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-test</artifactId> <scope>test</scope> </dependency> <dependency> <groupId>org.springframework.data</groupId> <artifactId>spring-data-rest-webmvc</artifactId> </dependency> <dependency> </dependencies> <build> <plugins> <plugin> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-maven-plugin</artifactId> </plugin> </plugins> </build> <repositories> <repository> <id>spring-releases</id> <name>Spring Releases</name> <url>https://repo.spring.io/libs-release</url> </repository> <repository> <id>org.jboss.repository.releases</id> <name>JBoss Maven Release Repository</name> <url>https://repository.jboss.org/nexus/content/repositories/releases</url> </repository> </repositories> <pluginRepositories> <pluginRepository> <id>spring-releases</id> <name>Spring Releases</name> <url>https://repo.spring.io/libs-release</url> </pluginRepository> </pluginRepositories> </project>
这是我的网络服务代码:
import org.springframework.web.bind.annotation.RequestBody; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod; import org.springframework.web.bind.annotation.RestController; @RestController @RequestMapping("/myservice") public class BaseService { @RequestMapping(value="/process", method = RequestMethod.POST) public void process(@RequestBody String payload) throws Exception { System.out.println(payload); } }
当我使用以下命令调用它时:
curl -H "Accept: application/json" -H "Content-type: application/json" -X POST -d '{"name":"value"}' http://localhost:8080/myservice/process
我收到此错误消息:
{"timestamp":1427515733546,"status":400, "error":"Bad Request", "exception": "org.springframework.http.converter.HttpMessageNotReadableException"," message": "Could not read JSON: Can not deserialize instance of java.lang.String out of START_OBJECT token\n at [Source: java.io.PushbackInputStream@8252f; line: 1, column: 1]; nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of java.lang.String out of START_OBJECT token\n at [Source: java.io.PushbackInputStream@8252f; line: 1, column: 1]", "path":"/myservice/process"
我唯一想做的就是传递一些有效的JSON(作为通过curl的字符串),并查看String有效负载是否以{“ name”:“ value”}的形式进入处理方法
我可能做错了什么?
感谢您抽出时间来阅读…
我认为使用JSON的最简单/便捷的方法是使用类似于JSON的Java类:http://codingdict.com/questions/6613 但是,如果您不能使用Java类,则可以使用这两种解决方案之一。
解决方案1: 您可以Map<String, Object>从控制器接收到它:
Map<String, Object>
@RequestMapping( value = "/process", method = RequestMethod.POST) public void process(@RequestBody Map<String, Object> payload) throws Exception { System.out.println(payload); }
使用您的请求:
curl -H "Accept: application/json" -H "Content-type: application/json" \ -X POST -d '{"name":"value"}' http://localhost:8080/myservice/process
解决方案2: 否则,您可以通过 以下 方式获取POST负载String:
String
@RequestMapping( value = "/process", method = RequestMethod.POST, consumes = "text/plain") public void process(@RequestBody String payload) throws Exception { System.out.println(payload); }
然后根据需要解析该字符串。请注意,必须consumes = "text/plain"在控制器上指定。在这种情况下,您必须使用以下命令更改您的请求Content-type: text/plain:
consumes = "text/plain"
Content-type: text/plain
curl -H "Accept: application/json" -H "Content-type: text/plain" -X POST \ -d '{"name":"value"}' http://localhost:8080/myservice/process