我正在使用Spring
Boot构建与LDAP集成的应用程序。我能够成功连接到LDAP服务器并验证用户身份。现在，我需要添加“记住我”功能。我试图浏览不同的帖子（this），但是找不到我的问题的答案。Spring Security官方文档指出

如果您使用的身份验证提供程序不使用UserDetailsS​​ervice（例如LDAP提供程序），那么它将不起作用，除非您在应用程序上下文中还具有UserDetailsS​​ervice
Bean

这是我的工作代码，带有一些最初的想法，可以添加“记住我”功能：

Web安全配置

import com.ui.security.CustomUserDetailsServiceImpl;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.access.event.LoggerListener;
import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.method.configuration.EnableGlobalMethodSecurity;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.ldap.authentication.ad.ActiveDirectoryLdapAuthenticationProvider;
import org.springframework.security.ldap.userdetails.UserDetailsContextMapper;
import org.springframework.security.web.authentication.RememberMeServices;
import org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices;

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    String DOMAIN = "ldap-server.com";
    String URL = "ldap://ds.ldap-server.com:389";


    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
                .csrf().disable()
                .authorizeRequests()
                .antMatchers("/ui/**").authenticated()
                .antMatchers("/", "/home", "/UIDL/**", "/ui/**").permitAll()
                .anyRequest().authenticated()
        ;
        http
                .formLogin()
                .loginPage("/login").failureUrl("/login?error=true").permitAll()
                .and().logout().permitAll()
        ;

        // Not sure how to implement this
        http.rememberMe().rememberMeServices(rememberMeServices()).key("password");

    }

    @Override
    protected void configure(AuthenticationManagerBuilder authManagerBuilder) throws Exception {

        authManagerBuilder
                .authenticationProvider(activeDirectoryLdapAuthenticationProvider())
                .userDetailsService(userDetailsService())
        ;
    }

    @Bean
    public ActiveDirectoryLdapAuthenticationProvider activeDirectoryLdapAuthenticationProvider() {

        ActiveDirectoryLdapAuthenticationProvider provider = new ActiveDirectoryLdapAuthenticationProvider(DOMAIN, URL);
        provider.setConvertSubErrorCodesToExceptions(true);
        provider.setUseAuthenticationRequestCredentials(true);
        provider.setUserDetailsContextMapper(userDetailsContextMapper());
        return provider;
    }

    @Bean
    public UserDetailsContextMapper userDetailsContextMapper() {
        UserDetailsContextMapper contextMapper = new CustomUserDetailsServiceImpl();
        return contextMapper;
    }

    /**
     * Impl of remember me service
     * @return
     */
    @Bean
    public RememberMeServices rememberMeServices() {
//        TokenBasedRememberMeServices rememberMeServices = new TokenBasedRememberMeServices("password", userService);
//        rememberMeServices.setCookieName("cookieName");
//        rememberMeServices.setParameter("rememberMe");
        return rememberMeServices;
    }

    @Bean
    public LoggerListener loggerListener() {
        return new LoggerListener();
    }
}

CustomUserDetailsS​​erviceImpl

public class CustomUserDetailsServiceImpl implements UserDetailsContextMapper {

    @Autowired
    SecurityHelper securityHelper;
    Log ___log = LogFactory.getLog(this.getClass());

    @Override
    public LoggedInUserDetails mapUserFromContext(DirContextOperations ctx, String username, Collection<? extends GrantedAuthority> grantedAuthorities) {

        LoggedInUserDetails userDetails = null;
        try {
            userDetails = securityHelper.authenticateUser(ctx, username, grantedAuthorities);
        } catch (NamingException e) {
            e.printStackTrace();
        }

        return userDetails;
    }

    @Override
    public void mapUserToContext(UserDetails user, DirContextAdapter ctx) {

    }
}

我知道我需要以某种方式实现UserService，但不确定如何实现。