Spring Boot mongoDB喜欢在数字字段上查询-整数/双精度

一尘不染

Spring Boot mongoDB喜欢在数字字段上查询-整数/双精度

spring-boot

我想在Spring Boot时对Integer / Double字段进行LIKE查询。
集合名称：球员

{
    "firstName" : "Lionel",
    "lastName" : "messi",
    "team" : "FC Barcelona",
    "salary" : 40000,
    "type" : "football"
},{
    "firstName" : : "Cristiano",
    "lastName" : "Ronaldo",
    "team" : "Real Madrid C.F.",
    "salary" : 35000,
    "type" : "football"
},{
    "firstName" : : "Neymar",
    "lastName" : "Jr",
    "team" : "Paris Saint-Germain F.C.",
    "salary" : 25000,
    "type" : "football"
},{
    "firstName" : "Luis",
    "lastName" : "Alberto",
    "team" : "FC Barcelona",
    "salary" : 25000,
    "type" : "football"
},{
    "firstName" : "Virat",
    "lastName" : "Kohali",
    "team" : "Indian Cricket Team",
    "salary" : 40000,
    "type" : "cricket"
}

而我的spring java代码如下生成查询。

String game = "football";
String team = "barcelona";
Double salary = 250;

Query query = new Query();
Set<String> gameType = new HashSet<>();
List<Criteria> andCriteria = new ArrayList<>();

gameType.add(game);

andCriteria.add(Criteria.where("type").in(gameType));
andCriteria.add(Criteria.where("team").regex(team,"i"));

Criteria[] criteriaArray = new Criteria[andCriteria.size()];
criteriaArray = andCriteria.toArray(criteriaArray);
query.addCriteria(new Criteria().andOperator(criteriaArray));

List<Players> players = mongoTemplate.find(query, Players.class);

return players;

查询：

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
        }
    },
    {
      "team": {
        $regex: "barcelona",
        $options: "i"
      }
    }]
})

上面的查询向我返回了2个文档，其中“类型”分别为“足球”和“团队”，如 巴塞罗那

{"firstName" : "Lionel", "lastName" : "messi", "team" : "FC Barcelona", "salary" : 40000, "type" : "football"},
{"firstName" : "Luis", "lastName" : "Alberto", "team" : "FC Barcelona", "salary" : 25000, "type" : "football"}

但我想查询“类型”为“足球”和“工资”像 250 在它

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
      }
    },
    {
      $where : "/^250.*/.test(this.salary)"
    }]
})

返回的结果如下。

{"firstName" : : "Neymar", "lastName" : "Jr", "team" : "Paris Saint-Germain F.C.", "salary" : 25000, "type" : "football"},
{"firstName" : "Luis", "lastName" : "Alberto", "team" : "FC Barcelona", "salary" : 25000, "type" : "football"}

先感谢您。

阅读 492

2020-05-30

共1个答案

一尘不染

我设法在双字段上建立LIKE查询。

Query query = new Query();
Set<String> gameType = new HashSet<>();
List<Criteria> andCriteria = new ArrayList<>();

String game = "football";
int salary = 250;

gameType.add(game);

andCriteria.add(Criteria.where("type").in(gameType));
andCriteria.add(Criteria.where("$where").is("/^" + salary + ".*/.test(this.salary)"));

Criteria[] criteriaArray = new Criteria[andCriteria.size()];
criteriaArray = andCriteria.toArray(criteriaArray);
query.addCriteria(new Criteria().andOperator(criteriaArray));

List<Players> players = mongoTemplate.find(query, Players.class);

return players;

正如我上面发布的那样，此代码段生成了LIKE。
您也可以用简单的方式做到这一点。

Query query = new Query();
Set<String> gameType = new HashSet<>();

String game = "football";
int salary = 250;

gameType.add(game);

query.addCriteria(Criteria.where("type").in(gameType));
query.addCriteria(Criteria.where("$where").is("/^" + salary + ".*/.test(this.salary)"));

List<Players> players = mongoTemplate.find(query, Players.class);

return players;

我希望这将有所帮助。

2020-05-30