我正在尝试在我的JPA存储库之一中选择内部联接

查询：

@Query(value = "select wm.WagerIdentification, wm.BoardNumber, wm.MarkSequenceNumber, wm.MarkNumber," +
        " pt.CouponTypeIdentification, pt.WagerBoardQuickPickMarksBoard " +
        "from WagerBoard wb " +
        "inner join wb.listOfWagerMarks wm on wb.WagerIdentification = wm.WagerIdentification and wb.BoardNumber = wm.BoardNumber and wb.GameIdentification = wm.GameIdentification and wm.meta_IsCurrent = 1 " +
        "inner join wb.poolgameTransaction pt on (wb.TransactionIdentification = pt.TransactionIdentification and pt.meta_IsCurrent = 1)" +
        "where wb.meta_IsCurrent = 1")
List<Object[]> findAllTest();

关系：

池游戏交易

@OneToMany(mappedBy = "poolgameTransaction")
private List<WagerBoard> ListOfWagers = new ArrayList<>();

赌板

@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
        @JoinColumn(name = "TransactionIdentification", insertable = false, updatable = false),
        @JoinColumn(name = "meta_CreatedDate", insertable = false, updatable = false)
})
private PoolgameTransaction poolgameTransaction;

@OneToMany(mappedBy = "wagerBoard")
private List<WagerBoardMarks> listOfWagerMarks;

赌注标记

@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
        @JoinColumn(name = "BoardNumber", insertable = false, updatable = false),
        @JoinColumn(name = "GameIdentification", insertable = false, updatable = false),
        @JoinColumn(name = "WagerIdentification", insertable = false, updatable = false),
        @JoinColumn(name = "meta_CreatedDate", insertable = false, updatable = false)
})
private WagerBoard wagerBoard;

错误：

Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: with-clause referenced two different from-clause elements