一尘不染

spring:客户端发送的请求在语法上不正确()

spring-mvc

嗨,我在重定向期间收到了下一个错误:

客户端发送的请求在语法上不正确

浏览器显示的URL是:localhost:8080/Project/menu/main/home/0在这里,我的类首先进行重定向-“从”重定向,然后进行“重定向”到:

 /*
 * Get all possible values of menu and generate correct url to pages controllers
 * 
 */

@Controller
@SessionAttributes("menu")
public class MainMenuController {


    @ModelAttribute
    public Menu createMenu() {
        return new Menu();
    }

    @RequestMapping(value = "/menu", method = RequestMethod.GET)
    public String mainMenuResolver(@ModelAttribute Menu menu) {
        menu.setMainMenu("first");
        return "forward:/menu/first";
    }

    @RequestMapping(value = "/menu/{mainMenu}", method = RequestMethod.GET)
    public String subMenuResolver(@PathVariable String mainMenu, @ModelAttribute Menu menu) {
        menu.setMainMenu(mainMenu);
        menu.setSubMenu("home");
        return "forward:/menu/first/home";
    }

    @RequestMapping(value = "/menu/{mainMenu}/{subMenu}", method = RequestMethod.GET)
    public String secMenuResolver(@PathVariable String mainMenu, @PathVariable String subMenu, @ModelAttribute Menu menu) {
        menu.setMainMenu(mainMenu);
        menu.setSubMenu(subMenu);
        menu.setSecMenu("0");

        if (menu.getMainMenu().equals("first")){
            return "redirect:/menu/main/"+menu.getSubMenu()+"/"+menu.getSecMenu();
        }

        if (menu.getMainMenu().equals("second")){
            return "redirect:/menu/religion/"+menu.getSubMenu()+"/"+menu.getSecMenu();
        }

        return "redirect:/menu/main/"+menu.getSubMenu()+"/"+menu.getSecMenu();
    }
}

第二类:

@Controller
@SessionAttributes("menu")
public class FirstPageController {

    @ModelAttribute
    public Menu createMenu() {
        return new Menu();
    }

    @RequestMapping(value = "/menu/main/{subMenu}/{secMenu}", method = RequestMethod.GET)
    public ModelAndView menuResolver(@PathVariable String mainMenu, @PathVariable String subMenu,@PathVariable String secMenu, @ModelAttribute("menu") Menu menu) {
        menu.setMainMenu(mainMenu);
        menu.setSubMenu(subMenu);
        menu.setSecMenu(secMenu);

        if (menu.getSubMenu().equals("home")){
            String title = "Project - Home Page";
            return new ModelAndView("MainPage", "title", title);
        }

        String title = "Project - Home Page";
        return new ModelAndView("MainPage", "title", title);
    }
}

解决 :我解决了它,第二类的方法中有多余的参数。


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2020-06-01

共1个答案

一尘不染

在这种情况下,将org.springframework.web登录级别设置为DEBUGinlog4j configuration

<logger name="org.springframework.web">
    <level value="DEBUG" />
    ...
</logger>

例如,当缺少参数或无法将其转换为所需的类型时,日志中将出现异常详细信息。

2020-06-01