我刚刚开始学习Spring MVC 3,开始运行简单的hello world程序时遇到了问题
我试图让这个启动和运行,但我不能因为某些原因
我不断收到这个错误
type Status report message / description The requested resource (/) is not available.
这是我的servlet-context.xml档案
servlet-context.xml
<?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure --> <!-- Enables the Spring MVC @Controller programming model --> <annotation-driven /> <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory --> <resources mapping="/resources/**" location="/resources/" /> <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory --> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> <context:component-scan base-package="com.test.test" /> </beans:beans>
web.xml 文件
web.xml
<?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <!-- The definition of the Root Spring Container shared by all Servlets and Filters --> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/root-context.xml</param-value> </context-param> <!-- Creates the Spring Container shared by all Servlets and Filters --> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <!-- Processes application requests --> <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>appServlet</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app>
HomeController.java
打包com.test.test;
import org.springframework.stereotype.Controller; import org.springframework.ui.Model; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod; @Controller public class HomeController { @RequestMapping(value = "/") public String home() { return "WEB-INF/views/home.jsp"; } }
我正在使用Tomcat 7。
有人知道这个错误是什么吗?
@Tenelope您不需要返回,"WEB-INF/views/home.jsp";您可以返回"home"它,因为您已经在servlet- context中对其进行了配置:
"WEB-INF/views/home.jsp";
"home"
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean>
我对您的建议是下载spring源(类似于IDE的Eclipse):
http://www.springsource.org/springsource-tool-suite- download
下载后,您只需转到 File > New > Spring Template Project > Spring MVC project
File > New > Spring Template Project > Spring MVC project
创建完项目后,将为您创建工作模板项目(结构化项目,示例控制器文件,示例视图,pom.xml等)。包括"/"您正在谈论的示例。您可以构建它并将其部署到tomcat或其他任何东西。
"/"
这样,您已经获得了有效的示例,您可以从那里获取它。
顺便说一句。看一下这个 :
https://github.com/SpringSource/spring-mvc- showcase/blob/master/MasteringSpringMVC3.pdf?raw=true
这足以使您开始使用Spring MVC。