一尘不染

Java:获取匹配项在字符串中的位置的方法?

java

String match = "hello";
String text = "0123456789hello0123456789";

int position = getPosition(match, text); // should be 10, is there such a method?

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2020-03-22

共1个答案

一尘不染

执行此操作的方法家族是:

  • int indexOf(String str)
  • indexOf(String str, int fromIndex)
  • int lastIndexOf(String str)
  • lastIndexOf(String str, int fromIndex)

返回指定子字符串的第一个(或最后一个)出现在此字符串内的索引[ 从指定索引处开始向前(或向后搜索)]。

String text = "0123hello9012hello8901hello7890";
String word = "hello";

System.out.println(text.indexOf(word)); // prints "4"
System.out.println(text.lastIndexOf(word)); // prints "22"

// find all occurrences forward
for (int i = -1; (i = text.indexOf(word, i + 1)) != -1; i++) {
    System.out.println(i);
} // prints "4", "13", "22"

// find all occurrences backward
for (int i = text.length(); (i = text.lastIndexOf(word, i - 1)) != -1; i++) {
    System.out.println(i);
} // prints "22", "13", "4"
2020-03-22