我有与此类似的JSON:
{ "unknown_field": { "field1": "str", "field2": "str", "field3": "str", "field4": "str", "field5": "str" }, ...... }
我创建了一些类来映射这个json
public class MyModel implements Serializable { private int id; private HashMap<String, Model1> models; // getters and setter for id and models here }
而Model1类是仅包含String字段的简单类。
但这是行不通的。
编辑:JSON格式如下所示:
{ "1145": { "cities_id": "1145", "city": "Nawanshahr", "city_path": "nawanshahr", "region_id": "53", "region_district_id": "381", "country_id": "0", "million": "0", "population": null, "region_name": "Punjab" }, "1148": { "cities_id": "1148", "city": "Nimbahera", "city_path": "nimbahera", "region_id": "54", "region_district_id": "528", "country_id": "0", "million": "0", "population": null, "region_name": "Rajasthan" }, ... }
Gson 2.0+的解决方案 我刚刚了解到,使用更新的Gson版本,这非常简单:
GsonBuilder builder = new GsonBuilder(); Object o = builder.create().fromJson(json, Object.class);
创建的对象是一个Map(com.google.gson.internal.LinkedTreeMap),如果你打印它,它看起来像这样:
{1145={cities_id=1145, city=Nawanshahr, city_path=nawanshahr, region_id=53, region_district_id=381, country_id=0, million=0, population=null, region_name=Punjab}, 1148={cities_id=1148, city=Nimbahera, city_path=nimbahera, region_id=54, region_district_id=528, country_id=0, million=0, population=null, region_name=Rajasthan} ...
使用自定义解串器的解决方案 (注意:除非你坚持使用Gson 2.0之前的版本,否则你并不是真正的自定义反序列化器。但是了解如何在Gson中进行自定义反序列化(和序列化)仍然很有用,并且通常最佳方法,具体取决于你要如何使用解析后的数据。)
因此,我们确实在处理随机/可变字段名称。(当然,这种JSON格式不是很好;这种数据应放在JSON数组中,在这种情况下,可以很容易地将其读入List。哦,我们仍然可以解析它。)
首先,这是我如何在Java对象中对JSON数据建模:
// info for individual city public class City { String citiesId; String city; String regionName; // and so on } // top-level object, containing info for lots of cities public class CityList { List<City> cities; public CityList(List<City> cities) { this.cities = cities; } }
然后,解析。处理此类JSON的一种方法是为顶级对象(CityList)创建自定义反序列化器。
像这样:
public class CityListDeserializer implements JsonDeserializer<CityList> { @Override public CityList deserialize(JsonElement element, Type type, JsonDeserializationContext context) throws JsonParseException { JsonObject jsonObject = element.getAsJsonObject(); List<City> cities = new ArrayList<City>(); for (Map.Entry<String, JsonElement> entry : jsonObject.entrySet()) { // For individual City objects, we can use default deserialisation: City city = context.deserialize(entry.getValue(), City.class); cities.add(city); } return new CityList(cities); } }
需要注意的关键点是重新jsonObject.entrySet()调出所有顶级字段(名称如“ 1145”,“ 1148”等)的调用。这个堆栈溢出的答案帮助我解决了这个问题。
jsonObject.entrySet()
在下面完成解析代码。请注意,你需要使用registerTypeAdapter()注册自定义序列化程序。
GsonBuilder builder = new GsonBuilder(); builder.registerTypeAdapter(CityList.class, new CityListDeserializer()); Gson gson = builder.setFieldNamingPolicy(LOWER_CASE_WITH_UNDERSCORES).create(); CityList list = gson.fromJson(json, CityList.class);