请帮助:)操作系统：Linux

在“ sleep（1000）;”中，此时“ top（显示Linux任务）”写给我7.7％MEM使用。valgrind：找不到内存泄漏。

我了解，正确编写，所有malloc结果均为NULL。但是，为什么在这段时间“睡眠”我的程序不会减少内存？缺少什么？

对不起，我的英语不好，谢谢

~ # tmp_soft
For : Is it free??  no
Is it free??  yes
For 0 
For : Is it free??  no
Is it free??  yes
For 1 
END : Is it free??  yes
END



〜＃顶部
  PID USER      PR  NI  VIRT  RES  SHR S %CPU %MEM    TIME+  COMMAND                                                                
23060 root      20   0  155m 153m  448 S    0  7.7   0:01.07 tmp_soft

全文：tmp_soft.c

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <unistd.h>

struct cache_db_s
{
 int       table_update;
 struct    cache_db_s * p_next;
};

void free_cache_db (struct cache_db_s ** cache_db)
{
 struct cache_db_s * cache_db_t;
 while (*cache_db != NULL)
 {
  cache_db_t = *cache_db;
  *cache_db = (*cache_db)->p_next;
  free(cache_db_t);
  cache_db_t = NULL;
 }
 printf("Is it free??  %s\n",*cache_db==NULL?"yes":"no");
}

void make_cache_db (struct cache_db_s ** cache_db)
{
 struct cache_db_s * cache_db_t = NULL;
 int n = 10000000;

 for (int i=0; i = n; i++)
 {
  if ((cache_db_t=malloc(sizeof(struct cache_db_s)))==NULL) {
   printf("Error : malloc 1 -> cache_db_s (no free memory) \n");
   break;
  }
  memset(cache_db_t, 0, sizeof(struct cache_db_s));

  cache_db_t->table_update = 1; // tmp

  cache_db_t->p_next = *cache_db;
  *cache_db = cache_db_t;
  cache_db_t = NULL;
 }
}

int main(int argc, char **argv)
{
 struct cache_db_s * cache_db = NULL;

 for (int ii=0; ii  2; ii++) {
  make_cache_db(&cache_db);
  printf("For : Is it free??  %s\n",cache_db==NULL?"yes":"no");
  free_cache_db(&cache_db);
  printf("For %d \n", ii);
 }

 printf("END : Is it free??  %s\n",cache_db==NULL?"yes":"no");
 printf("END \n");
 sleep(1000);
 return 0;
}