一尘不染

如何模拟pyunit的stdin输入?

linux

我正在尝试测试从中获取输入的函数stdin,而我目前正在使用类似以下内容进行测试:

cat /usr/share/dict/words | ./spellchecker.py

以测试自动化的名义,有什么方法pyunit可以伪造输入raw_input()


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2020-06-02

共1个答案

一尘不染

简短的答案是猴子补丁 raw_input()

这是一个使用a的简单示例lambda,该示例丢弃提示并返回我们想要的内容。

被测系统

cat ./name_getter.py
#!/usr/bin/env python

class NameGetter(object):

    def get_name(self):
        self.name = raw_input('What is your name? ')

    def greet(self):
        print 'Hello, ', self.name, '!'

    def run(self):
        self.get_name()
        self.greet()

if __name__ == '__main__':
    ng = NameGetter()
    ng.run()

$ echo Derek | ./name_getter.py 
What is your name? Hello,  Derek !

测试用例:

$ cat ./t_name_getter.py
#!/usr/bin/env python

import unittest
import name_getter

class TestNameGetter(unittest.TestCase):

    def test_get_alice(self):
        name_getter.raw_input = lambda _: 'Alice'
        ng = name_getter.NameGetter()
        ng.get_name()
        self.assertEquals(ng.name, 'Alice')

    def test_get_bob(self):
        name_getter.raw_input = lambda _: 'Bob'
        ng = name_getter.NameGetter()
        ng.get_name()
        self.assertEquals(ng.name, 'Bob')

if __name__ == '__main__':
    unittest.main()

$ ./t_name_getter.py -v
test_get_alice (__main__.TestNameGetter) ... ok
test_get_bob (__main__.TestNameGetter) ... ok

----------------------------------------------------------------------
Ran 2 tests in 0.000s

OK
2020-06-02