旧版应用程序的PAM身份验证

一尘不染

旧版应用程序的PAM身份验证

linux

我有一个旧版应用程序，该应用程序通过网络异步接收用户名/密码请求。由于我已经将用户名和密码存储为变量，因此在Linux（Debian
6）上通过PAM进行身份验证的最佳方法是什么？

我尝试编写自己的对话功能，但不确定将密码输入其中的最佳方法。我已经考虑过将其存储在appdata中，并从pam_conv结构中引用它，但是几乎没有关于该操作的文档。

有没有一种简单的方法来对用户进行身份验证而又不会过度使用对话功能？我也无法成功使用pam_set_data，我不确定这是否合适。

这是我在做什么：

user = guiMessage->username;
pass = guiMessage->password;

pam_handle_t* pamh = NULL;
int           pam_ret;
struct pam_conv conv = {
  my_conv,
  NULL
};

pam_start("nxs_login", user, &conv, &pamh);
pam_ret = pam_authenticate(pamh, 0);

if (pam_ret == PAM_SUCCESS)
  permissions = 0xff;

pam_end(pamh, pam_ret);

最初尝试使用对话功能导致（密码经过硬编码以进行测试）：

int 
my_conv(int num_msg, const struct pam_message **msg, struct pam_response **resp, void *data)
{
  struct pam_response *aresp;

  if (num_msg <= 0 || num_msg > PAM_MAX_NUM_MSG)
    return (PAM_CONV_ERR);
  if ((aresp = (pam_response*)calloc(num_msg, sizeof *aresp)) == NULL)
    return (PAM_BUF_ERR);
  aresp[0].resp_retcode = 0;
  aresp[0].resp = strdup("mypassword");

  *resp = aresp;
  return (PAM_SUCCESS);
}

任何帮助，将不胜感激。谢谢！

阅读 269

2020-06-07

共1个答案

一尘不染

这就是我最终要做的。请参阅标有三个星号的注释。

#include <stdlib.h>
#include <iostream>
#include <fstream>
#include <security/pam_appl.h>
#include <unistd.h>

// To build this:
// g++ test.cpp -lpam -o test

// if pam header files missing try:
// sudo apt install libpam0g-dev

struct pam_response *reply;

//function used to get user input
int function_conversation(int num_msg, const struct pam_message **msg, struct pam_response **resp, void *appdata_ptr)
{
  *resp = reply;
  return PAM_SUCCESS;
}

int main(int argc, char** argv)
{
  if(argc != 2) {
      fprintf(stderr, "Usage: check_user <username>\n");
      exit(1);
  }
  const char *username;
  username = argv[1];

  const struct pam_conv local_conversation = { function_conversation, NULL };
  pam_handle_t *local_auth_handle = NULL; // this gets set by pam_start

  int retval;

  // local_auth_handle gets set based on the service
  retval = pam_start("common-auth", username, &local_conversation, &local_auth_handle);

  if (retval != PAM_SUCCESS)
  {
    std::cout << "pam_start returned " << retval << std::endl;
    exit(retval);
  }

  reply = (struct pam_response *)malloc(sizeof(struct pam_response));

  // *** Get the password by any method, or maybe it was passed into this function.
  reply[0].resp = getpass("Password: ");
  reply[0].resp_retcode = 0;

  retval = pam_authenticate(local_auth_handle, 0);

  if (retval != PAM_SUCCESS)
  {
    if (retval == PAM_AUTH_ERR)
    {
      std::cout << "Authentication failure." << std::endl;
    }
    else
    {
      std::cout << "pam_authenticate returned " << retval << std::endl;
    }
    exit(retval);
  }

  std::cout << "Authenticated." << std::endl;

  retval = pam_end(local_auth_handle, retval);

  if (retval != PAM_SUCCESS)
  {
    std::cout << "pam_end returned " << retval << std::endl;
    exit(retval);
  }

  return retval;
}

2020-06-07