我正在使用执行查询

select lastlevel as VERSION,name as DESCRIPTION,
TO_DATE(lastdate, 'DDMONYYYY_HH24:MI:SS') as RELEASEDATE
from mytable where rownum<=10

这列lastdate是varchar类型

得到这样的结果

Version     Release Date        
1.0         2002-11-22

2.0     2003-02-08

我在这里设置上述查询的结果，这里setLastDate是日历类型，所以我在类似方法中设置发布日期的结果

if (rs.getString("VERSION") != null ) {             bean.setLastLevel(rs.getString("VERSION").trim());
}

if (rs.getDate("RELEASEDATE") != null ) 
{
Calendar calendar = Calendar.getInstance();
calendar.setTime(rs.getDate("RELEASEDATE"));
bean.setLastDate(calendar);
}

像2003-02-08这样在bean中设置该值。最后，我将这个结果bean添加到数组列表“ list”中，例如list.add（bean）;。

现在我想在jsp中使用所有这些值。我正在使用spring mvc，所以我用arraylist“ list”返回视图。当我像这样迭代jsp中的值时

<c:forEach var="list" items="${list}">
<td valign="top">${list.lastLevel}</td>
<td valign="top">${list.lastDate}</td>
</c:forEach>

在jsp而不是获取日期，我越来越像这样

Version     Release Date        
1.0          java.util.GregorianCalendar[time=1037775600000,areFieldsSet=true,

areAllFieldsSet = true，lenient = true，zone = sun.util.calendar.ZoneInfo [id =“
US / Arizona”，offset = -25200000，dstSavings = 0，useDaylight =
false，transitions = 12，lastRule = null]，firstDayOfWeek =
1，minimalDaysInFirstWeek = 1，ERA = 1，YEAR = 2002，MONTH = 10，WEEK_OF_YEAR =
47，WEEK_OF_MONTH = 4，DAY_OF_MONTH = 20，DAY_OF_YEAR = 324，DAY_OF_WEEK =
4，DAY_OF_WEEK_IN_MONTH = 3，AM_PM = 0，HOUR = 0， HOUR_OF_DAY = 0，MINUTE =
0，SECOND = 0，MILLISECOND = 0，ZONE_OFFSET = -25200000，DST_OFFSET = 0]

2.0          java.util.GregorianCalendar[time=1044687600000,areFieldsSet=true,
areAllFieldsSet=true,lenient=true,zone=sun.util.calendar.ZoneInfo[id="US/Arizona",offset=-25200000,dstSavings=0,useDaylight=false,transitions=12,lastRule=null],firstDayOfWeek=1,minimalDaysInFirstWeek=1,ERA=1,YEAR=2003,MONTH=1,WEEK_OF_YEAR=6,WEEK_OF_MONTH=2,DAY_OF_MONTH=8,DAY_OF_YEAR=39,DAY_OF_WEEK=7,DAY_OF_WEEK_IN_MONTH=2,AM_PM=0,HOUR=0,HOUR_OF_DAY=0,MINUTE=0,SECOND=0,MILLISECOND=0,ZONE_OFFSET=-25200000,DST_OFFSET=0]

请帮我解决这个问题。我需要得到结果的日期。如何解决这个问题。提前致谢。