在通过SearchQuery进行搜索时,我试图查看和使用每个匹配项的_score。除了别的以外,这还可以知道我的搜索在哪个分数范围内。但是除了使用searchQuery.withMinScore(float)设置MinScore之外;我找不到任何方法来处理搜索分数。
@Override public Page<Website> listsearch(SearchBody searchBody, int size, int page) { BoolQueryBuilder qb = QueryBuilders.boolQuery(); for(SearchUnit unit:searchBody.getSearchBody()){ if(unit.isPriority()) { qb.must(matchQuery("_all", unit.getWord()).operator(MatchQueryBuilder.Operator.AND) .fuzziness(Fuzziness.AUTO)); }else { qb.should(termQuery("_all", unit.getWord()) .boost(unit.getWeight())); } } for(SearchUnit ExUnit:searchBody.getExcludeBody()){ qb.mustNot(matchPhraseQuery("_all",ExUnit.getWord())); } SearchQuery searchQuery = new NativeSearchQueryBuilder() .withIndices("websites_v1") .withTypes("website") .withQuery(qb) .withMinScore(0.05F)//Magical minscore .withPageable(new PageRequest(page, size)) .build(); Page<Website> search = searchRepository.search(searchQuery); return search; }
使用的搜索功能来自org.springframework.data.elasticsearch.repository; 定义为
Page<T> search(SearchQuery var1);
所以我的问题是无论如何我都可以访问页面中每个返回对象的分数?还是我需要将查询方法切换到其他方法才能实现?
使用Spring Data ElasticSearch存储库是不可能的。
您需要自动连接an EntityMapper和an ElasticSearchTemplate并自己提取分数。这样的事情应该起作用:
EntityMapper
ElasticSearchTemplate
Pageable pageRequest = new PageRequest(0, 10); Page<Website> result = elasticSearchTemplate.query(searchQuery, new ResultsExtractor<Page<Website>>() { @Override public Page<Website> extract(SearchResponse response) { List<Website> content = new ArrayList<>(); SearchHit[] hits = response.getHits().getHits(); for (SearchHit hit : hits) { Website website = entityMapper.mapToObject(hit, Website.class); content.add(website); float documentScore = hit.getScore(); // <---- score of a hit } return new PageImpl<Website>(content, pageRequest, response.getHits().getTotalHits()); } });