一尘不染

使用Python在Selenium Webdriver中通过URL上传图像

selenium

driver.find_element(By.XPATH, "//*[@id='upl-zone']/input").send_keys("https://ercess.com//images//events//-Blockchain-2019-36613-banner.png")

有什么办法可以使它工作?

[错误]
selenium.common.exceptions.InvalidArgumentException:消息:未找到文件:https
:
//ercess.com//images//events//-Blockchain-2019-36613-banner.png


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2020-06-26

共1个答案

一尘不染

您首先需要将图像下载到计算机上,然后将其上传…

您可以使用requests

import requests

URL = "https://ercess.com//images//events//-Blockchain-2019-36613-banner.png"
picture_req = requests.get(URL)
if picture_req.status_code == 200:
    with open("/path/to/image.jpg", 'wb') as f:
        f.write(picture_req.content)

然后发送/path/to/image.jpg

driver.find_element(By.XPATH, "//*[@id='upl-zone']/input").send_keys("/path/to/image.jpg")

或者您可以使用Legacy interfaceurllib您将使用urlretrieve

import urllib.request

URL = "https://ercess.com//images//events//-Blockchain-2019-36613-banner.png"
urllib.urlretrieve(URL, "file_name.png")
driver.find_element(By.XPATH, "//*[@id='upl-zone']/input").send_keys("file_name.png")

编辑:

要使用send_keys将路径发送到文件,您可以使用
pathlib

from pathlib import Path

# `cwd`: current directory is straightforward
cwd = Path.cwd()
# using "F"string for format you can use: image_file_name = str(cwd) + "\" + "file_name.png" 
image_file_name = fr"{cwd}\file_name.png"
# this print is just to show the image_file_name   
print(image_file_name)

希望这对您有所帮助!

2020-06-26