R如何在不知道长度的情况下进行for循环？

一尘不染

R如何在不知道长度的情况下进行for循环？

selenium

目前，我正在此站点上抓取图表图表信息。要抓取信息，我需要为有很多镜头的情况做一个for循环。我可以通过单击“
Team Stats”并找到射门次数来找到射门次数。

我想做出适当的选择for loop而不必找出拍摄数量。

我目前正在做什么：

shotchart <- data.frame(shot=as.vector(0), class=as.vector(0), data_homeaway=as.vector(0), 
                    data_period=as.vector(0), player_id=as.vector(0), data_text=as.vector(0),
                    location=as.vector(0), gamenumber= as.vector(0))

for (i in 1:54)
{
 text <-paste0("//*[(@class='shots home-team')]//*[(@id)][",i,"]")
 shotchart[nrow(shotchart)+1,1]<- unlist(re$findElement(using='xpath',text)$getElementAttribute('id'))
shotchart[nrow(shotchart),2]<- unlist(re$findElement(using='xpath', text)$getElementAttribute('class'))
shotchart[nrow(shotchart),3]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-homeaway'))
shotchart[nrow(shotchart),4]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-period'))
shotchart[nrow(shotchart),5]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-shooter'))
shotchart[nrow(shotchart),6]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-text'))
shotchart[nrow(shotchart),7]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('style'))
shotchart[nrow(shotchart),8]<-k-1

}

任何帮助将不胜感激。请让我知道是否需要进一步的信息。

阅读 356

2020-06-26

共1个答案

一尘不染

library(RSelenium)
checkForServer()
startServer()
Sys.sleep(5)
re<-remoteDriver()
re$open()
re$navigate("http://espn.go.com/mens-college-basketball/playbyplay?gameId=400830392")

shotchart <- data.frame(shot=as.vector(0), class=as.vector(0), data_homeaway=as.vector(0), 
                        data_period=as.vector(0), player_id=as.vector(0), data_text=as.vector(0),
                        location=as.vector(0), gamenumber= as.vector(0))
error="Error : \t Summary: NoSuchElement\n \t Detail: An element could not be located on the page using the given search parameters.\n \t class: org.openqa.selenium.NoSuchElementException\n"
i<-1
element=0
while ((i>0)&(element[1]!=error))
{
  text <-paste0("//*[(@class='shots home-team')]//*[(@id)][",i,"]")
  element<- try(unlist(re$findElement(using='xpath', text)$getElementAttribute('id')),silent = TRUE)
  if (element[1]==error)
    break;
  shotchart[nrow(shotchart)+1,1]<- unlist(re$findElement(using='xpath',text)$getElementAttribute('id'))
  shotchart[nrow(shotchart),2]<- unlist(re$findElement(using='xpath', text)$getElementAttribute('class'))
  shotchart[nrow(shotchart),3]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-homeaway'))
  shotchart[nrow(shotchart),4]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-period'))
  shotchart[nrow(shotchart),5]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-shooter'))
  shotchart[nrow(shotchart),6]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('data-text'))
  shotchart[nrow(shotchart),7]<-unlist(re$findElement(using='xpath', text)$getElementAttribute('style'))
  shotchart[nrow(shotchart),8]<-i-1
  i<-i+1
}

我不确定您的变量k是什么意思。

我从所有评论中获得了建议。

2020-06-26