如何使用selenium和scrapy来自动化该过程？

一尘不染

如何使用selenium和scrapy来自动化该过程？

selenium

我曾经知道您需要使用诸如selenium之类的webtoolkit来自动执行抓取。

我将如何能够单击Google Play商店上的下一个按钮，以便仅出于我的大学目的刮取评论！

import scrapy
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.selector import Selector
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from urlparse import urljoin
from selenium import webdriver
import time


class Product(scrapy.Item):
    title = scrapy.Field()


class FooSpider(CrawlSpider):
    name = 'foo'

    start_urls = ["https://play.google.com/store/apps/details?id=com.gaana&hl=en"]

    def __init__(self, *args, **kwargs):
        super(FooSpider, self).__init__(*args, **kwargs)
        self.download_delay = 0.25
        self.browser = webdriver.Chrome(executable_path="C:\chrm\chromedriver.exe")
        self.browser.implicitly_wait(60) #

    def parse(self,response):
        self.browser.get(response.url)
        sites = response.xpath('//div[@class="single-review"]/div[@class="review-header"]')
        items = []
        for i in range(0,200):
            time.sleep(20)
            button = self.browser.find_element_by_xpath("/html/body/div[4]/div[6]/div[1]/div[2]/div[2]/div[1]/div[2]/button[1]/div[2]/div/div")
            button.click()
            self.browser.implicitly_wait(30)    
            for site in sites:
                item = Product()

                item['title'] = site.xpath('.//div[@class="review-info"]/span[@class="author-name"]/a/text()').extract()
                yield item

我已经更新了代码，一次又一次重复地给了我40个项目。for循环怎么了？

似乎正在更新的源代码没有传递到xpath，这就是为什么它返回相同的40个项目的原因

阅读 330

2020-06-26

共1个答案

一尘不染

我会做这样的事情：

from scrapy import CrawlSpider
from selenium import webdriver
import time

class FooSpider(CrawlSpider):
    name = 'foo'
    allow_domains = 'foo.com'
    start_urls = ['foo.com']

    def __init__(self, *args, **kwargs):
        super(FooSpider, self).__init__(*args, **kwargs)
        self.download_delay = 0.25
        self.browser = webdriver.Firefox()
        self.browser.implicitly_wait(60)

    def parse_foo(self.response):
        self.browser.get(response.url)  # load response to the browser
        button = self.browser.find_element_by_xpath("path") # find 
        # the element to click to
        button.click() # click
        time.sleep(1) # wait until the page is fully loaded
        source = self.browser.page_source # get source of the loaded page
        sel = Selector(text=source) # create a Selector object
        data = sel.xpath('path/to/the/data') # select data
        ...

不过，最好不要等待固定的时间。因此time.sleep(1)，您可以使用 http://www.obeythetestinggoat.com/how-
to-get-selenium-to-wait-for-page-load-after-a-
click.html中介绍的方法之一来代替。

2020-06-26