这个问题是由于chrome driver总clicks的中间element在试图忠实于什么实际用户一样。所以我在想这种方法:
chrome driver
clicks
element
首先,而不是查找元素,然后单击:
driver.fineElement(By.xpath("bla bla")).click()
编写单击以下内容的通用函数WebElement:
WebElement
def clickOnWebElement(WebElement webElement) { int counter = 0; boolean isClicked = false; Thread.sleep(1000); try { while (count < 2 && !isClicked) { if (count == 0) { webElement.click() isClicked = true; } else if (count == 1) { Actions action = new Actions(driver); action.moveToElement(webElement).click().perform(); isClicked = true; } else if (count == 2) { JavascriptExecutor js =(JavascriptExecutor)driver; js.executeScript("window.scrollTo(0,"element.getLocation().x+")"); webElement.click(); isClicked = true; } } } catch(Exception ex) { count++; Thread.sleep(2000); } }
然后,当发生此异常时,请尝试以其他方式单击。
您认为这种方法可行吗?
请仔细阅读此堆栈溢出答案以更好地理解。
更新 我们也可以尝试
There are many Conditions that we can use withing Webdriver tests. 1. visibilityOf(WebElement element) : An expectation for checking that an element, known to be present on the DOM of a page, is visible. 2. visibilityOfElementLocated(By locator) : An expectation for checking that an element is present on the DOM of a page and visible. In the above two conditions we are waiting for an element to be present on the DOM of a page and also visible. These works fine only when the element is loaded completely.
也请尝试如下
尝试使用Y坐标单击
WebElement elementToClick = driver.findElement(By.xpath("Your xpath")); // Scroll the browser to the element's Y position ((JavascriptExecutor)driver).executeScript("window.scrollTo(0,"+elementToClick.getLocation().y+")"); // Click the element elementToClick.click();
尝试使用X坐标单击
WebElement elementToClick = driver.findElement(By.xpath("Your xpath")); // Scroll the browser to the element's X position ((JavascriptExecutor)driver).executeScript("window.scrollTo(0,"+elementToClick.getLocation().x+")"); // Click the element elementToClick.click();
希望这对您有帮助