一尘不染

如何从网址中删除查询?

scrapy

我正在使用scrapy抓取一个似乎在每个URL末尾向查询字符串添加随机值的网站。这将爬网变成一种无限循环。

我如何抓紧忽略URL的查询字符串部分?


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2020-04-10

共1个答案

一尘不染

示例代码:

from urlparse import urlparse
o = urlparse('http://url.something.com/bla.html?querystring=stuff')

url_without_query_string = o.scheme + "://" + o.netloc + o.path

输出示例:

Python 2.6.1 (r261:67515, Jun 24 2010, 21:47:49) 
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> from urlparse import urlparse
>>> o = urlparse('http://url.something.com/bla.html?querystring=stuff')
>>> url_without_query_string = o.scheme + "://" + o.netloc + o.path
>>> print url_without_query_string
http://url.something.com/bla.html
>>> 
2020-04-10