一尘不染

如何在Go中清除切片?

go

在Go中清除切片的适当方法是什么?

这是我在go论坛中找到的内容:

// test.go
package main

import (
    "fmt"
)

func main() {
    letters := []string{"a", "b", "c", "d"}
    fmt.Println(cap(letters))
    fmt.Println(len(letters))
    // clear the slice
    letters = letters[:0]
    fmt.Println(cap(letters))
    fmt.Println(len(letters))
}

这样对吗?

为了澄清起见,清除了缓冲区,以便可以重用它。

一个示例是bytes包中的Buffer.Truncate函数。

请注意,Reset只是调用Truncate(0)。因此看来,在这种情况下,第70行将评估:b.buf = b.buf [0:0]

http://golang.org/src/pkg/bytes/buffer.go

// Truncate discards all but the first n unread bytes from the buffer.
60  // It panics if n is negative or greater than the length of the buffer.
61  func (b *Buffer) Truncate(n int) {
62      b.lastRead = opInvalid
63      switch {
64      case n < 0 || n > b.Len():
65          panic("bytes.Buffer: truncation out of range")
66      case n == 0:
67          // Reuse buffer space.
68          b.off = 0
69      }
70      b.buf = b.buf[0 : b.off+n]
71  }
72  
73  // Reset resets the buffer so it has no content.
74  // b.Reset() is the same as b.Truncate(0).
75  func (b *Buffer) Reset() { b.Truncate(0) }

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2020-07-02

共1个答案

一尘不染

这完全取决于您对“透明”的定义。有效的方法之一当然是:

slice = slice[:0]

但是有一个陷阱。如果切片元素的类型为T:

var slice []T

然后强制len(slice)为零,由上述“特技”, 使任何元件

slice[:cap(slice)]

eligible for garbage collection. This might be the optimal approach in some
scenarios. But it might also be a cause of “memory leaks” - memory not used,
but potentially reachable (after re-slicing of ‘slice’) and thus not garbage
“collectable”.

2020-07-02